Answer:
Verified that he oscillations are exactly isosynchronous with frequency ω0 = p g/l, independent of the amplitude.
Explanation:
Starting from the first principle for the derivation and to prove that the oscillations are exactly isosynchronous with frequency ω0 = p g/l, independent of the amplitude. The mathematical manipulations was applied, trigonometric identities was also applied.The steps and explanation are shown in the attachment.
Typebars
Turbocars
Teacups
Teapoys
Tourneys
Toecaps
Trepangs
Tabourers
Trouncers
Troupers
Terraces
Trances
Turbans
Toupees
Toucans
Sorry if this is not what you want me to do and I just threw a bunch of words at you.
Answer:
1) 10.05 N/m
2) 20.69 m
Explanation:
1) If the jumper completes 8 cycles in 49 seconds, then the period of each cycles is T = 49/8 = 6.125 s
From this info we can calculate the spring constant, treating this as simple harmonic motion k:
2) Let g = 9.8 m/s2. So the jumper weight is F = mg = 60*9.8 = 588 N. With this force the jumper would have stretched the bungee a length of
x = F/k = 588 / 63.14 = 9.31 m
As the jumper is at rest 30m below the bridge and the cord is stretched by 9.31m. Then its original length would be 30 - 9.31 = 20.69 m
It would be B) because if the tank was to leak it would be harmful
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