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3 years ago

5. Analyze When you use a

Physics

1 answer:

Ad libitum [116K]3 years ago

3 0

Answer: I don’t know Kiane I’m looking for the anwser too—Gianny

Explanation:

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what makes the moon rise in the east,travel across earths sky and set in the west each day? this is for science can someone plz

Anna71 [15]

Earths Rotation makes the moon travel

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4 years ago

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Alexeev081 [22]

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3 years ago

If the 78.0 kg astronaut were in a spacecraft 6R from the center of the earth, what would the astronaut's weight be on earth? 76

den301095 [7]

(a) 764.4 N

The weight of the astronaut on Earth is given by:

$F=mg$

where

m is the astronaut's mass

g is the acceleration due to gravity

Here we have

m = 78.0 kg

g = 9.8 m/s^2 at the Earth's surface

So the weight of the astronaut is

$F=(78.0)(9.8)=764.4 N$

(b) 21.1 N

The spacecraft is located at a distance of

$r=6R$

from the center of Earth.

The acceleration due to gravity at a generic distance r from the Earth's center is

$g=\frac{GM}{r^2}$

where G is the gravitational constant and M is the Earth's mass.

We know that at a distance of r = R (at the Earth's surface) the value of g is 9.8 m/s^2, so we can write:

$GM=9.8R^2$ (1)

the acceleration due to gravity at r=6R instead will be

$g'=\frac{GM}{(6R)^2}$

And substituting (1) into this formula,

$g'=\frac{9.8R^2}{36R^2}=0.27 m/s^2$

So the weight of the astronaut at the spacecratf location is

$F'=mg'=(78.0 kg)(0.27 m/s^2)=21.1 N$

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4 years ago

El segundero de un reloj tiene 2cm de longitud. Determínese, para un punto en el extremo libre de la manecilla (considerando =

Zina [86]

Answer:

LET THE BODIES HIT THE FLOOOR

Step-by-step explanation:

Answer:

Step-by-step explanation:

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3 years ago

What is the frequency of radiation whose wavelength is 11.5 a0 ?

irakobra [83]

Answer:

The frequency of radiation is $2.61 \times 10^{17} s^{-1}$

Explanation:

Given:

Wavelength $\lambda = 11.5 \times 10^{-10}$ m

Speed of light $c = 3 \times 10^{8}$ $\frac{m}{s}$

For finding the frequency of radiation,

$c = f \lambda$

$f = \frac{c}{\lambda}$

$f = \frac{3 \times 10^{8} }{11.5 \times 10^{-10} }$

$f = 2.61 \times 10^{17}$ $s^{-1}$

Therefore, the frequency of radiation is $2.61 \times 10^{17} s^{-1}$

4 0

3 years ago