An object moves in simple harmonic motion described by the equation d equals one fifth sine 2 t where t is measured in seconds a
1 answer:
Answer:
The maximum displacement, the frequency, and the time required for one cycle are 1/5 inch, 1/π Hz and π sec.
Explanation:
Given that,
The equation of simple harmonic motion
.....(I)
We need to calculate the maximum amplitude
Using equation of simple harmonic motion
Where, a = amplitude
=frequency
t = time
On comparing equation (I) and general equation
The amplitude is a maximum displacement traveled by a wave.
So, the maximum displacement is
We need to calculate the frequency
We need to calculate the time required for one cycle
Hence, The maximum displacement, the frequency, and the time required for one cycle are 1/5 inch, 1/π\ Hz and π\ sec.
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(a) Work done by the electric field is 12 J on a 0.0001 C of charge. The electric potential is defined as the work done per unit charged particles. It is given by :
(b) Similarly, same electric field does 24 J of work on a 0.0002-C charge. The electric potential difference is given by :
Therefore, this is the required solution.
Answer:
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Explanation:
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