A 1600kg cannon fires a 5kg cannonball horizontally. The exit velocity of the cannonball is 80m/s and the barrel length is 2m. W
1 answer:
Answer:
a = 1600 m / s²
Explanation:
For this exercise we use the kinematics relations,
v² = v₀² + 2 a x
where v₀ is the initial velocity of the bullet, which as part of rest is zero, for the distance (x) we can assume that the gases accelerate along the entire trajectory of the cannon x = 2m
a =
let's calculate
a =
a = 1600 m / s²
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Part a)
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Part c)
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Answer:
Explanation:
Answer:
(a) 28690 m/s (b)
Explanation:
The orbital speed is define as:
(1)
Where r is the radius of the trajectory and T is the orbital period.
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(2)
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(3)
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⇒
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Kepler’s third law is defined as:
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It is necessary to pass from meters to astronomical unit (AU), 1 AU is defined as the distance between the Earth and the Sun.
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Finally, equation 1 can be used:
<u>So Earth orbital speed around the Sun is 28690 m/s.</u>
<em>b) What is its kinetic energy?</em>
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(4)
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(5)
M will be isolated in equation 5:
Where r is the radius of the Earth ()
<u>Hence, the kinetic energy of Earth is .</u>