The magnitude of the velocity of the truck relative to the car is 183.9 km/h
The direction of the velocity of the truck relative to the car is 67 ⁰ north of west.
<h3>Velocity of the truck relative to the car</h3>
The velocity of the truck relative to the car is the resultant velocity of the vehicles.
The resultant velocity of the car is calculated as follows;
<h3>Vertical component of the velocity</h3>
Vyi = 119 km/h
Vy2 = 87.7 km/h x sin(35) = 50.3 km/h
Vy(total) = 119 km/h + 50.3 km/h = 169.3 km/h
<h3>Horizontal component of the velocity</h3>
Vx = -87.7 x cos(35) = -71.84 km
<h3>Resultant velocity</h3>
v = √Vy² + Vx²
v = √[(169.3²) + (-71.84)²]
v = 183.9 km/h
<h3>Direction of the velocity</h3>
θ = arc tan(Vy/Vx)
θ = arc tan(169.3 / -71.84)
θ = -67 ⁰
θ = 67 ⁰ north of west.
Thus, the magnitude of the velocity of the truck relative to the car is 183.9 km/h and the direction of the velocity of the truck relative to the car is 67 ⁰ north of west.
Learn more about resultant velocity here: brainly.com/question/24767211
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