Write as many fractions as you can that are greater than one and less than two, with a denominator of three
1 answer:
Step-by-step explanation:
and
are two fractions that are greater than 1 but less than 2 with a denominator of 3;
The denominator is the lower number in a quotient
Numerator is the upper number in a quotient
To solve this problem, we need to think creatively:
A fraction is made up of a numerator and denominator.
The denominator in this case must be 3
The numerator can be any number;
since the solution of our fraction must be greater than 1, this implies that the numerator must higher than the denominator.
if the denominator is higher, we get a solution less than 1.
since the solution must be less than 2, the value lies between 1 and 2.
The solution to the problem is and
learn more:
fraction brainly.com/question/1757979
#learnwithBrainly
You might be interested in
Answer:
1) Null hypothesis:
Alternative hypothesis:
2) estimated proportion of people indicated that they watch the late evening news on this local CBS station
3)
And we can use the following excel code to find it: "=NORM.INV(0.01,0,1)"
4)
5)
And we can use the following excel code to find it: "=NORM.INV(0.1,0,1)"
6) We see that so then we have enough evidence to FAIL to reject the null hypothesis at 1% of significance.
7) Null hypothesis:
Step-by-step explanation:
Data given and notation
n=100 represent the random sample taken
X represent the people indicated that they watch the late evening news on this local CBS station
estimated proportion of people indicated that they watch the late evening news on this local CBS station
is the value that we want to test
represent the significance level
Confidence=95% or 0.95
z would represent the statistic (variable of interest)
Alternative hypothesis:
Part 2
estimated proportion of people indicated that they watch the late evening news on this local CBS station
Part 3
Since we have a left tailed test we need to see in the normal standard distribution a value that accumulates 0.01 of the area on the left and on this case this value is :
And we can use the following excel code to find it: "=NORM.INV(0.01,0,1)"
Part 4
When we conduct a proportion test we need to use the z statisitc, and the is given by:
(1)
Since we have all the info requires we can replace in formula (1) like this:
Part 5
Since we have a left tailed test we need to see in the normal standard distribution a value that accumulates 0.1 of the area on the left and on this case this value is :
And we can use the following excel code to find it: "=NORM.INV(0.1,0,1)"
Part 6
We see that so then we have enough evidence to FAIL to reject the null hypothesis at 1% of significance.
Part 7
Null hypothesis: