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kramer
3 years ago
11

the number of blocks had 9 in the ones place. The number in the hundreds place is one more than the numbers in the tens place. T

hose two numbers equal 11. How many blocks are there
Mathematics
1 answer:
Ray Of Light [21]3 years ago
4 0
659 blooooooooocks lol (:


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Find the quotient −40÷20.
sukhopar [10]

Answer:

-2

Step-by-step explanation:

7 0
2 years ago
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Who’s right? And why?
kvasek [131]

Answer: Raymond is correct

The DJ charges $75 an hour.

=================================================

Explanation:

x = number of hours

y = total cost

The DJ does a 3-hour event for $275. This means one point is (x,y) = (3,275)

Another point is (5,425) because a 5-hour event costs $425.

Let's find the slope of the line through these two points.

(x_1,y_1) = (3,275) \text{ and } (x_2,y_2)  = (5,425)\\\\m = \frac{y_{2} - y_{1}}{x_{2} - x_{1}}\\\\m = \frac{425 - 275}{5 - 3}\\\\m = \frac{150}{2}\\\\m = 75\\\\

The slope is 75, meaning that each time y goes up by 75, x goes up by 1.

Flipped around it means each time x goes up by 1, y goes up by 75.

This means each time we add on an extra hour, the cost goes up by $75.

The DJ charges $75 an hour. Raymond is correct.

3 0
2 years ago
Solve the system of equations.
Sloan [31]

Answer:

b.

( -3, -5)

Step-by-step explanation:

6x + 13 = 2x + 1

6x -2x = 1-13

4x = -12

x = -12/4 = -3

y = 6x + 13

y = 6(-3) +13 = -18+13 = -5

(x, y) = (-3,-5)

7 0
2 years ago
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The Band Booster club sells beverages for $1.47 and candy for $1.61 at home games. Their goal is to have total sales of $229.11
evablogger [386]
Answer: D) 1.47x + 1.61y = 229.11

Explanation: The amount of beverages and candy sold combined (addition) should be set equal to the targeted goal per game ($229.11).
4 0
3 years ago
Find the length of QP given Q is the midpoint of XF, PQ =2X+1, XF=7X-4, PF=X
nadezda [96]

Answer:

Therefore the length of QP = 3.4 units

Step-by-step explanation:

Given:

PQ = 2x + 1

XF = 7x - 4

PF = x

Q is the mid poimt of XF

∴ XQ = QF

QF = PQ - PF  ..........( Q - F - P )

     = 2x + 1 - x

∴ QF      = x + 1

∴ XQ = QF = x + 1

TO Find:

QP = ?

Solution:

By Addition Property we have

XP = XQ + QF+PF ..........(X-Q-F-P)\\\\

XF + PF =XQ + QF+PF ..........(X-Q-F-P)\\

Substituting the given values in above equation we get

(7x - 4) + x = (x +1) + (x +1) + x

8x -4 = 3x +2

8x - 3x + 4 + 2

5x = 6

∴ x = \frac{6}{5}

Now we require

QP = (2x + 1)

∴ QP = 2\times \frac{6}{5} +1\\\\QP = \frac{12+5}{5} \\\\QP =\frac{17}{5} \\\\\therefore QP = 3.4\ unit

Therefore the length of QP = 3.4 units

3 0
2 years ago
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