Answer:
CO(g) + 2H₂(g) → CH₃OH(l)
Explanation:
Carbon monoxide has molecular formula CO, molecular hydrogen has formula H₂, and methanol is CH₃OH.
The reactants are CO and H₂ and the product CH₃OH:
CO(g) + H₂(g) → CH₃OH(l)
To balance the equation, the elements must have the same amount on each side. C and O are balanced, but there is 4H in the product and only 2 in the reactant, so we multiply H₂ for 2:
CO(g) + 2H₂(g) → CH₃OH(l)
And the equation is balanced.
Percent yield represents to what extent the reaction runs to completion. In this, the theoretical yield is 50 grams (100% completion).
To calculate percent yield, divide the actual by the theoretical. In doing so, the percent yield is 88% (44/50).
W=F*d
W= 500 J
F = 250 N
500 J = 250 N * d
d= 500J/250 N = 2 J/N = 2(N*m)/N = 2 m
Answer is 2 m.
