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blondinia [14]
3 years ago
8

What is the mass, in grams, of 1.26 mol of water, H2O?

Chemistry
1 answer:
Masteriza [31]3 years ago
8 0

Answer:

The mass of 1.26 mole of water, H₂O, is 22.68 grams

Explanation:

Molar mass is the amount of mass that a substance contains in one mole. In other words, the molar mass of an atom or a molecule is the mass of one mole of that particle and its unit is g/mole.

In this case, being:

  • H: 1 g/mole
  • O: 16 g/mole

the molar mass of water H₂O is:

H₂O= 2*1 g/mole + 16 g/mole= 18 g/mole

Then you can apply the following rule of three: if 18 grams are present in 1 mole of H2O, how much mass is present in 1.26 moles of water?

mass=\frac{1.26 moles*18 grams}{1 mole}

mass= 22.68 grams

<u><em>The mass of 1.26 mole of water, H₂O, is 22.68 grams</em></u>

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How many molecules are in 41.8 g of sulfuric acid
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Answer

× 10²³ molecules are in 41.8 g of sulfuric acid

Explanation

The first step is to convert 41.8 g of sulfuric acid to moles by dividing the mass of sulfuric acid by its molar mass.

Molar mass of sulfuric acid, H₂SO₄ = 98.079 g/mol

Mole=\frac{Mass}{Molar\text{ }mass}=\frac{41.8\text{ }g}{98.079\text{ }g\text{/}mol}=0.426187053\text{ }mol

Finally, convert the moles of sulfuric acid to molecules using Avogadro's number.

Conversion factor: 1 mole of any substance = 6.022 × 10²³ molecules.

Therefore, 0.426187053 moles of sulfuric acid is equal

\frac{0.426187053\text{ }mol}{1\text{ }mol}\times6.022×10²³\text{ }molecules=2.57\times10^{23}\text{ }molecules

Thus, 2.57 × 10²³ molecules are in 41.8 g of sulfuric acid.

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