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3 years ago

What happens on the side of the earth opposite the moon

Chemistry

2 answers:

Lostsunrise [7]3 years ago

8 0

It will be day time and the other side will be night time

juin [17]3 years ago

6 0

Wouldn't the side of the Earth that is opposite to the moon be experiencing day time? I'm not sure what you're asking. It would be exposed to the Sun.

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What is critical mass?

Alinara [238K]

Answer:

the smallest mass of material that can sustain a chain reaction

Explanation:

Critical mass refers to the smallest possible mass of a fissionable material that can sustain a chain reaction

3 0

3 years ago

Read 2 more answers

What is the formula ofchromium(III) hydrogensulfate?

FromTheMoon [43]

Answer:

Cr (HSO4)3

Explanation:

its molecular weight is 343.20 g/mol

its molecular formula can also be written as CrH3O12S3

molar mass of Cr (HSO4)3 can be calculated by following method;

atomic mass of Cr = 51.9961 u

atomic mass of H = 1 u

atomic mass of S = 32.065 u

atomic mass of O = 16 u

molar mass of Cr(HSO4)3 = 51.9961+ 1.00784×3 + 32.065×3 + 15.999×12

molar mass of Cr(HSO4)3 =51.9961+3.02352+96.195+ 191.988

molar mass of Cr(HSO4)3 = 343.20 g/mol

3 0

3 years ago

A rigid vessel contains 3.98 kg of refrigerant-134a at 700 kPa and 60°C. Determine the volume of the vessel and the total intern

Arada [10]

<u>Answer:</u> The volume of the vessel is $0.1542m^3$ and total internal energy is 162.0 kJ.

<u>Explanation:</u>

To calculate the volume of water, we use the equation given by ideal gas, which is:

$PV=nRT$

or,

$PV=\frac{m}{M}RT$

where,

P = pressure of container = 700 kPa

V = volume of container = ? L

m = Given mass of R-134a = 3.98 kg = 3980 g (Conversion factor: 1kg = 1000 g)

M = Molar mass of R-134a = 102.03 g/mol

R = Gas constant = $8.31\text{L kPa }mol^{-1}K^{-1}$

T = temperature of container = $60^oC=[60+273]K=333K$

Putting values in above equation, we get:

$700kPa\times V=\frac{3980g}{102.03g/mol}\times 8.31\text{L kPa }\times 333K\\\\V=154.21L$

Converting this value into $m^3$ , we use the conversion factor:

$1m^3=1000L$

So, $\Rightarrow (\frac{1m^3}{1000L})\times 154.21L$

$\Rightarrow 0.1542m^3$

To calculate the internal energy, we use the equation:

$U=\frac{3}{2}nRT$

or,

$U=\frac{3}{2}\frac{m}{M}RT$

where,

U = total internal energy

m = given mass of R-134a = 3.98 kg = 3980 g (Conversion factor: 1kg = 1000g)

M = molar mass of R-134a = 102.03 g/mol

R = Gas constant = $8.314J/K.mol$

T = temperature = $60^oC=[60+273]K=333K$

Putting values in above equation, we get:

$U=\frac{3}{2}\times \frac{3980g}{102.03g/mol}\times 8.314J/K.mol\times 333K\\\\U=161994.6J$

Converting this into kilo joules, we use the conversion factor:

1 kJ = 1000 J

So, 161994.6 J = 162.0 kJ

Hence, the volume of the vessel is $0.1542m^3$ and total internal energy is 162.0 kJ.

6 0

3 years ago

Question 18 (Essay Worth 8 points)

DENIUS [597]

Yes, the law of conservation of mass holds.

Explanation:

In every chemical reaction, mass is always conserved. This implies that in chemical reaction, the process proceeds maintaining the same set of atom in the same proportion without new ones forming.

From the description given, decomposition of the Silver carbonate will produce a silver residue with the given mass.
The other mass that seems lost can be examined to be given off as carbon dioxide gas which is the other product of the reaction and oxygen.
Therefore, since the products are silver, carbon dioxide and oxygen, the remaining mass is that of the carbon dioxide and oxygen. It is not lost.

learn more:

brainly.com/question/6837993

brainly.com/question/8912651

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4 0

3 years ago

You have just completed assaying the change in absorbance for an enzyme. The initial absorbance was 0.022; the absorbance after

Hitman42 [59]

Answer:

The answer is 0.844/10 minutes

Explanation:

You have an enzyme that catalizes a reaction which gives a product that can be quantified by an absorbance measurement. The more reaction time, the more product quantity and higher absorbance.

The rate of the reaction is the change in products quantity per time unit. As you are using the absorbance as a measure of the product quantity, you can calculate the rate as the change in absorbance (ΔA) per time (in minutes) as follows:

rate= ΔA/time

rate= (final absorbance - initial absorbance) /minutes

rate= (0.444-0.022)/5 min

rate= 0.422/5 min

In 10 minutes will be :

rate= 0.844/10 min

Commonly, a rate is the relation between two quantities measured in different units. For example, the speed of a car is the change in meters (traveled distance) per time (m/s or km/h). For an enzyme, is the same (quantity of product/time).

4 0

3 years ago