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Sever21 [200]
3 years ago
8

Which set of coefficients would be needed to balance the chemical equation below?

Chemistry
1 answer:
solong [7]3 years ago
3 0

Answer:

2Zn2+3O2 ----> 2ZnO+2SO2

Explanation:

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A laser pulse with wavelength 555 nm contains 4.40 mj of energy. how many photons are in the laser pulse?
Diano4ka-milaya [45]

Wavelength is the ratio of speed of light and frequency:

wavelength = speed of light / frequency 

where frequency is: (c is speed of light)<span>
freq = c / wavelength = 3E8/550E-9 = 5.45E14 Hz 

We know that photons have energy E = hf = 6.626E-34 Js * 5.45E14 Hz = 3.61 E-19 J 

Therefore if it has 4.40 mJ of energy, the pulse has: 
<span>4.40E-3/3.61E-19 = 1.22E16 photons</span></span>

5 0
3 years ago
Which is one way that scientists ensure that data is reliable?
docker41 [41]

Answer:

letter b by replicating experiments

Explanation:

8 0
2 years ago
What is the number of electron and neutron protons in atom 35?
Fittoniya [83]
The mass number = protons + neutrons. Bromine has a mass number of 80<span> and 35 protons so </span>80<span>-35 = </span>45<span> neutrons. b) How many electrons does the neutral atom of bromine have? The neutral atom of bromine has 35 electrons because the number of electrons equals the number of protons.</span>
6 0
3 years ago
Question 5
Nonamiya [84]

Answer:

chemical change

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burning and cooking are both chemical changes.

6 0
3 years ago
Calculate the number of hydrogen atoms present in 40g of urea, (NH2)2CO
tekilochka [14]

Answer: There are 16.14 \times 10^{23} atoms of hydrogen are present in 40g of urea, (NH_{2})_{2}CO.

Explanation:

Given: Mass of urea = 40 g

Number of moles is the mass of substance divided by its molar mass.

First, moles of urea (molar mass = 60 g/mol) are calculated as follows.

Moles = \frac{mass}{molar mass}\\= \frac{40 g}{60 g/mol}\\= 0.67 mol

According to the mole concept, 1 mole of every substance contains 6.022 \times 10^{23} atoms.

So, the number of atoms present in 0.67 moles are as follows.

0.67 mol \times 6.022 \times 10^{23} atoms/mol\\= 4.035 \times 10^{23} atoms

In a molecule of urea there are 4 hydrogen atoms. Hence, number of hydrogen atoms present in 40 g of urea is as follows.

4 \times 4.035 \times 10^{23} atoms\\= 16.14 \times 10^{23} atoms

Thus, we can conclude that there are 16.14 \times 10^{23} atoms of hydrogen are present in 40g of urea, (NH_{2})_{2}CO.

7 0
3 years ago
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