Find an equation in standard form for the hyperbola with vertices at (0, ±4) and foci at (0, ±5).

Mathematics

1 answer:

Zigmanuir [339]4 years ago

5 0

Answer:b

Step-by-step explanation: Cause I took the test

You might be interested in

Josie has 43 animal books and 29 art books. she puts all the books on 8 shelves. She puts the same number of books on each shelf

LenKa [72]

Answer:

Step-by-step explanation:

4 0

2 years ago

The profit earned by selling a quantity of x + 2 of a product is given by the expression x4 − x3 − 24. What is the average profi

Agata [3.3K]

the profit is a polynomial function :
p(x) = x^4 − x^3 − 24
the average profit per unit of product sold is :
ap(x) = (x^4 − x^3 − 24)/(x+2)

now,
(-2) is an "obvious" zero of p(x)
therefore : p(x) is dividable by (x+2)
and
the long division of p(x) by (x+2) gives :

Answer:
ap(x) = x^3 - 3x^2 + 6x - 12

8 0

4 years ago

Read 2 more answers

The first steps in writing f(x) = 4x2 + 48x + 10 in vertex form are shown.

seraphim [82]

Keywords:

<em>Quadratic equation, vertex shape, parabola </em>

For this case we have to rewrite the given quadratic equation, in the form of vertex, for this, we must take into account that a quadratic equation of the form $ax ^ 2 + bx + c = 0$ , can be rewritten in the form of vertex as: $y = a (x-h) ^ 2 + k.$ Vertice is the lowest or highest point of the parabola. The vertex is given by: $(h, k)$ . So, let: $f (x) = 4x ^ 2 + 48x + 10$ , to find the equation in the form of vertex, we follow the steps below: