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Ahat [919]
4 years ago
4

Maureen takes notes in class. Wave Interactions I. With Gases: A. Interference II. With Objects: A. Absorption B. Transmission a

. Refraction C. Reflection D. Diffraction Which line of Maureen’s notes contains an error? I II II B II D
Physics
1 answer:
Alexus [3.1K]4 years ago
8 0

Answer:

I

Explanation:

Wave interaction is a phenomenon that explains how waves interact with the matter around us like. air, water, etc. There are different types of wave interactions like refraction, reflection, interference, and diffraction.

(i) Refraction occurs when a wave passes through a transparent surface and it bends slightly due to the change in its speed.

(ii) Reflection occurs when the wave strikes on a polished surface and bounce back in the same medium. In this wave, interaction light doesn't enter into the surface.

(iii) Interference occurs when two waves interact with each other at the same time and form a resultant wave of greater or lower amplitude.

(iv) Diffraction takes place when a wave passes along obstacles or through the slit. Due to which bending of light takes place.

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A 200. kg object is pushed 12.0 m to the top of an incline to a height of 6.0 m. If the force applied along the incline is 3000.
Nataliya [291]

Answer:

Approximately 1.2 \times 10^{4}\; {\rm J} (assuming that g = 9.81\; {\rm N \cdot kg^{-1}}.)

Explanation:

The strength of the gravitational field near the surface of the earth is approximately constant: g = 9.81\; {\rm N \cdot kg^{-1}}.

The change in the gravitational potential energy ({\rm GPE}) of an object near the surface of the earth is proportional to the change in the height of this object. If the height of an object of mass m increased by \Delta h, the {\rm GPE} of that object would have increased by m\, g\, \Delta h.

In this question, the height of this object increased by \Delta h = 6.0\; {\rm m}. The mass of this object is m = 200\; {\rm kg}. Thus, the {\rm GPE} of this object would have increased by:

\begin{aligned}& (\text{Change in GPE}) \\ =\; & m\, g\, \Delta h \\ =\; & 200\; {\rm kg} \times 9.81\; {\rm N \cdot kg^{-1}} \times 6.0\; {\rm m} \\ \approx\; & 1.2 \times 10^{4}\; {\rm J}\end{aligned}.

(Note that 1\; {\rm N \cdot m} = 1\; {\rm J}.)

3 0
2 years ago
A water heater warms 35 l of water from a temperature of 22.7 c to a temperature of 83.7
fgiga [73]
The amount of energy needed to increase the temperature of a substance by \Delta T is given by
Q=m C_s \Delta T
where
m is the mass of the substance
C_s is its specific heat capacity
\Delta T is the increase in temperature

The water volume is V=35 L= 35 dm^3 = 0.035 m^3, since its density is d=1000 kg/m^3, the mass of this sample of water is
m=dV=(1000 kg/m^3)(0.035 m^3)=35 kg

The water specific heat capacity is C_s = 4.18 kJ/kg ^{\circ}C

and the increase in temperature is \Delta T=83.7 ^{\circ}C-22.7 ^{\circ}C=61^{\circ}C

Therefore, the amount of energy needed is
Q=mC_s \Delta T=(35 kg)(4.18 kJ/kg ^{\circ}C)(61^{\circ}C)=8924 kJ = 8.92 \cdot 10^6 J
8 0
4 years ago
(No files or links) Which of the following is a defining property of gases?
MariettaO [177]
The answer for this is d
6 0
3 years ago
An alpha particle travels at a velocity of magnitude 520 m/s through a uniform magnetic field of magnitude 0.034 T. (An alpha pa
Keith_Richards [23]

Answer:

(a) Magnetic force F=38.584\times 10^{-19}N

(b) Acceleration a=5.846\times 10^8m/sec^2

(C) Speed will remain same

Explanation:

We have given velocity of alpha particle v = 520 m/sec

Magnetic field B = 0.034 T

Charge on alpha particle q=3.2\times 10^{-19}C

Mass of alpha particle m=6.6\times 10^{-27}kg

Angle between velocity and magnetic field 43°

(a) Force acting on the particle is equal to

F=q(v\times B)=qvBsin\Theta

F=3.2\times 10^{-19}\times 320\times 0.034\times sin43^{\circ}

F=38.584\times 10^{-19}N

(B) According to newton's law

F = ma. here m is mass and a is acceleration.

So acceleration

a=\frac{F}{m}=\frac{38.584\times 10^{-19}}{6.6\times 10^{-27}}=5.846\times 10^8m/sec^2

(c) As the magnetic force is always perpendicular to velocity so speed will remain same neither decreases nor increases.

4 0
3 years ago
The diagram shows two balls before they collide.
Ronch [10]

Answer:

The Answer is B)0.2 kg • m/s

Explanation:

I made a 100 on my test. Sorry if I'm late but hope I helped.

4 0
3 years ago
Read 2 more answers
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