<u>Answer:</u>
The force F applied to the handle = 330.03 N
<u>Explanation:</u>
The force can be resolved in to two, horizontal component and vertical component. If θ is the angle between horizontal and applied force we have
Horizontal component of force = F cos θ
Vertical component of force = F sin θ
In this problem normal force exerted on the suitcase is 160 N, that is vertical component of force = 160 N and angle θ = 29⁰.
So, F sin 29 = 160
F = 330.03 N
The force F applied to the handle = 330.03 N
Answer:
T=21.7 min
Explanation:
The volume of one mole of gas at STP is
22.4 L
10.0 L
then has
n'=10.0/22.4 moles
the total energy released is then
Et= (10.0/22.4)* 286 kJ
Et=127.678 KJ
Power*time = energy, so time = energy/power =
Power=100W
Power=100 J/s
T= 127.6785kJ/100J/s = 1277 sec
T=1276.78sec/60min=21.3 min
I am quite certain that it is B, a lipid!
Answer:
115.32125 m/s
Explanation:
Distance = 70 cm
Angular speed
Angular displacement
Time taken will be
Speed of the bullet would be
The speed of the bulletis 115.32125 m/s