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mr_godi [17]
3 years ago
7

Which is the currrent SI unit to use in measuring the amount of material contained in a solid sphere

Physics
1 answer:
olya-2409 [2.1K]3 years ago
3 0
Hey

SI unit for measure the amount of material contained in a solid sphere metre cube(m^3).

mean it have Volume .
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Paleobotany is the study of fossil insects. True False
alexira [117]

Answer:

False

Explanation:

Paleobotany is the study of fossil plants.

6 0
3 years ago
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The radius of a sphere is increasing at a rate of 4 mm/s. How fast is the volume increasing when the diameter is 60 mm?
jok3333 [9.3K]
V = [4/3]π r^3 => [dV / dr ] = 4π r^2

[dV/dt] = [dV/dr] * [dr/dt]

[dV/dt] = [4π r^2] * [ dr/ dt]

r = 60 mm, [dr / dt] = 4 mm/s

[dV / dt ] = [4π(60mm)^2] * 4mm/s = 180,955.7 mm/s 


5 0
3 years ago
Current flows through a resistor; (a) with no direction since it is not a vector (b) from any potential to any different potenti
kykrilka [37]

Answer:

c)From high potential to low potential.

Explanation:

Given that

current is flowing through resister.

As we know that those quantity have direction as well as magnitude then these are called vector quantity and those quantity have only magnitude then they called scalar quantity.

As we know that current have direction as well as magnitude so current is a vector quantity.

Current flows from high potential to low potential.

8 0
3 years ago
Reese can run 10 meter in 5 seconds.What is her speed?
Bad White [126]

Answer:

2 meters per second

Explanation:

4 0
3 years ago
An object weighs 79.1 N in air. When it is suspended from a force scale and completely immersed in water the scale reads 21.8 N.
Free_Kalibri [48]

Answer:

(a). The density of the object is 1382 kg/m³.

(b). The density of the oil is 536.4 kg/m³.

Explanation:

Given that,

Weight in air = 79.1 N

Weight in water = 21.8 N

Weight in oil = 48.4 N

We need to calculate the volume of object

Using formula of buoyant force

F_{b}=W_{air}=W_{water}

F_{b}=79.1-21.8

F_{b}=57.3\ N

F_{b}=\rho g h

Put the value into the formula

57.3=1000\times V\times 9.8

V=\dfrac{57.3}{1000\times9.8}

V=5.84\times10^{-3}\ m^3

We need to calculate the density

Using formula of buoyant force

F_{b}=\rho Vg

79.1=\rho\times5.84\times10^{-3}\times9.8

\rho=\dfrac{79.1}{5.84\times10^{-3}\times9.8}

\rho=1382\ kg/m^3

The density of the object is 1382 kg/m³.

(b). We need to calculate the volume of object

Using formula of buoyant force

F_{b}=W_{air}=W_{oil}

F_{b}=79.1-48.4

F_{b}=30.7\ N

We need to calculate the density

Using formula of buoyant force

F_{b}=\rho_{oil} Vg

30.7=\rho_{oil}\times5.84\times10^{-3}\times9.8

\rho_{oil}=\dfrac{30.7}{5.84\times10^{-3}\times9.8}

\rho=536.4\ kg/m^3

The density of the oil is 536.4 kg/m³.

Hence, This is the required solution.

4 0
3 years ago
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