As per the question the body possesses kinetic energy but the net displacement of the particle is zero.
Before going to explain the type of motion first we have to know the basics of displacement.
The displacement is a vector quantity which has magnitude as well as direction .it is the minimum distance between two points out of all possible paths
Let us consider an example .let a body travels from point A to the point B and again comes to the back to the same point A .here the distance traveled is 2AB but the net displacement is zero.we have to apply this concept to solve this problem.
As the body possesses kinetic energy but the net displacement is zero .
This is in case of an circular motion.in circular motion the body possesses rotational kinetic energy but in every circular rotation ,the net displacement is zero.
One can take an example of oscillatory motion also.here the particle possesses vibrational kinetic energy ,but in each vibration ,the net displacement is zero.
Answer:
Rolling = Riding a bicycle on a sidewalk
Static = Pushing a car unsuccessfully
Sliding = Pulling your computer across the bed
Fluid = Throwing a soccer ball to your friend
Two north poles would push away from each other
Answer:
0 N
Explanation:
Net force = mass × acceleration
∑F = ma
The velocity is constant, so the acceleration is 0. Therefore, the net force is 0.
Explanation:
The rod can be in equilibrium only if the resultant force is 0 and the moment around any point of the rod must be equal to 0.
We have to take moments around the pivoted point.
Moment = Force × Perpendicular distance to the force
For the rod to be in equilibrium,
Clockwise moment - Anticlockwise moment = 0
Clockwise moment = Anticlockwise moment
The distance between pivoted point and the weight of rod = 50 cm - 30 cm = 20 cm
So 20 cm× 1.2 N produces a Clockwise moment
If Perpendicular distance between pivoted point and 2N load is x,
Anticlockwise moment = x × 2N
20 cm× 1.2N = 2N × x
x = 12 cm
So 2 N load is at 12 from the pivoted point.
From the left edge of the meter ruler, 2N load is at 30-12 cm distance
= 18 cm