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3 years ago

7

The science club advisor expects that between 42 and 49 students will attend Science Club field trip. The school allows $5.50 pe

r student for sandwiches and drinks. What is the advisors budget for food for the trip?

1 answer:

baherus [9]3 years ago

8 0

Answer:

$269.50

Step-by-step explanation:

Between 42-49

So, you have to assume 49 students will arrive, better to have more and have left overs than get less and not find kids.

As for math you just do 49 x 5.50 = 269.5

Finally that measn the budget for the food is $269.50

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A jet moving at constant speed traveled 6,600 km in 3 hours. What was the speed of the jet?

DanielleElmas [232]

Answer:

The speed of the jet is $2,200\frac{km}{h}$

Step-by-step explanation:

The speed traveled by the jet can be found using the relationship between distance and time. Because the problem gives the values for distance and time, they must be replaced in the equation and in this way the requested speed will be found.

1. Write the general equation for the speed:

$Speed=\frac{Distance}{Time}$

2. Replace the values of distance and time on the general equation for the speed and make the mathematical operations:

$Speed=\frac{6,600km}{3hours}$

$Speed=2,200\frac{km}{h}$

Therefore the speed of the jet is $2,200\frac{km}{h}$

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3 years ago

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HELP ASAP!!!!!!!!

Hoochie [10]

Answer:

Step-by-step explanation:

The set {1,2,3,4,5,6} has a total of 6! permutations

a. Of those 6! permutations, 5!=120 begin with 1. So first 120 numbers would contain 1 as the unit digit.

b. The next 120, including the 124th, would begin with '2'

c. Then of the 5! numbers beginning with 2, there are 4!=24 including the 124th number, which have the second digit =1

d. Of these 4! permutations beginning with 21, there are 3!=6 including the 124th permutation which have third digit 3

e. Among these 3! permutations beginning with 213, there are 2 numbers with the fourth digit =4 (121th & 122th), 2 with fourth digit 5 (numbers 123 & 124) and 2 with fourth digit 6 (numbers 125 and 126).

Lastly, of the 2! permutations beginning with 2135, there is one with 5th digit 4 (number 123) and one with 5 digit 6 (number 124).

∴ The 124th number is 213564

Similarly reversing the above procedure we can determine the position of 321546 to be 267th on the list.

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2 years ago

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Approximate area under the curve f(x) =-x^2+2x+4 from x=0 to x=3 by using summation notation with six rectangles and use the the

bekas [8.4K]

Answer:

Summation notation:

$\frac{1}{2}\sum_{k=1}^6f((.5k))$

or after using your function part:

$\frac{1}{2}\sum_{k=1}^6(-(.5k)^2+2(.5k)+4)$

After evaluating you get 11.125 square units.

Step-by-step explanation:

The width of each rectangle is the same so we want to take the distance from x=0 to x=3 and divide by 6 since we want 6 equal base lengths for our rectangles.

The distance between x=0 and x=3 is (3-0)=3.

We want to divide that length of 3 units by 6 which gives a length of a half per each base length.

We are doing right endpoint value so I'm going to stat at x=3. The first rectangle will be drawn to the height of f(3).

The next right endpoint is x=3-1/2=5/2=2.5, and the second rectangle will have a height of f(2.5).

The next will be at x=2.5-.5=2, and the third rectangle will have a height of f(2).

The fourth rectangle will have a height of f(2-.5)=f(1.5).

The fifth one will have a height of f(1.5-.5)=f(1).

The last one because it is the sixth one will have a height of f(1-.5)=f(.5).

So to find the area of a rectangle you do base*time.

So we just need to evaluate:

$\frac{1}{2}f(3)+\frac{1}{2}f(2.5)+\frac{1}{2}f(2)+\frac{1}{2}f(1.5)+\frac{1}{2}f(1)+\frac{1}{2}f(.5)$

or by factoring out the 1/2 part:

$\frac{1}{2}(f(3)+f(2.5)+f(2)+f(1.5)+f(1)+f(.5))$

To find f(3) replace x in -x^2+2x+4 with 3:

-3^2+2(3)+4

-9+6+4

1

To find f(2.5) replace x in -x^2+2x+4 with 2.5:

-2.5^2+2(2.5)+4

-6.25+5+4

2.75

To find f(2) replace x in -x^2+2x+4 with 2:

-2^2+2(2)+4

-4+4+4

4

To find (1.5) replace x in -x^2+2x+4 with 1.5:

-1.5^2+2(1.5)+4

-2.25+3+4

4.75

To find f(1) replace x in -x^2+2x+4 with 1:

-1^2+2(1)+4

-1+2+4

5

To find f(.5) replace x in -x^2+2x+4 with .5:

-.5^2+2(.5)+4

-.25+1+4

4.75

Now let's add those heights. After we obtain this sum we multiply by 1/2 and we have our approximate area:

$\frac{1}{2}(f(3)+f(2.5)+f(2)+f(1.5)+f(1)+f(.5))$

$\frac{1}{2}(1+2.75+4+4.75+5+4.75)$

$\frac{1}{2}(22.25)$

$11.125$

Okay now if you wanted the summation notation for:

$\frac{1}{2}(f(3)+f(2.5)+f(2)+f(1.5)+f(1)+f(.5))$

is it

$\frac{1}{2}\sum_{k=1}^{6}(f(.5+.5(k-1)))$

or after simplifying a bit:

$\frac{1}{2}\sum_{k=1}^6 f((.5+.5k-.5))$

$\frac{1}{2}\sum_{k=1}^6f((.5k))$

If you are wondering how I obtain the .5+.5(k-1):

I realize that 3,2.5,2,1.5,1,.5 is an arithmetic sequence with first term .5 if you the sequence from right to left (instead of left to right) and it is going up by .5 (reading from right to left.)

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3 years ago

What is y=4x^2-9x+1 in vertex form

Anna11 [10]

Answer:

$y = 4 \left(x - \dfrac{9}{8} \right)^2 - \dfrac{65}{16}$

Step-by-step explanation:

$y = 4x^2 - 9x + 1$

You need to complete the square on the right side.

$y = (4x^2 - 9x) + 1$

$y = 4(x^2 - \dfrac{9}{4}x) + 1$

$y = 4 \left( x^2 - \dfrac{9}{4}x + \left( \dfrac{9}{8} \right)^2 \right) + 1 - 4\left( \dfrac{9}{8} \right)^2$

$y = 4 \left(x - \dfrac{9}{8} \right)^2 + 1 - 4 \left( \dfrac{81}{64} \right)$

$y = 4 \left(x - \dfrac{9}{8} \right)^2 + 1 - \dfrac{81}{16}$

$y = 4 \left(x - \dfrac{9}{8} \right)^2 + \dfrac{16}{16} - \dfrac{81}{16}$

$y = 4 \left(x - \dfrac{9}{8} \right)^2 - \dfrac{65}{16}$

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3 years ago

A black bear has a tail 190 mm long.How many cm is that?

GarryVolchara [31]

Answer:19

Step-by-step explanation:

Divide 190 by 10

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3 years ago

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