Simplify the complex fraction 2/3 1/3

I need help on #3, #4,5,6

Stolb23 [73]

It may be

3.
10x+5y

5(2x)+5(y)

4.
20x-15

5.
-6f-11
6.
-24w+12x

7 0

4 years ago

Help please i realllyy need help

vredina [299]

2 and 5/8: You would go from the number the fraction is closest to, and then add the fraction itself.

3 0

3 years ago

Read 2 more answers

What is 34 divided by 86.465

arsen [322]

Rounded up to 0.4

ffffffffff

8 0

4 years ago

Which best describes Imara’s error?

Sati [7]

<h2>Answer:</h2>

The statement that best describes Imara's error is:

Option: D

D). She did not find the side lengths of the square with an area of 625.

<h2>Step-by-step explanation:</h2>

Imara correctly did the previous calculation.

i.e. she correctly determined the area of square with side length 20 units (as 400 square units) and 15 units (i.e. 225 square units)

But when she sum the area of two squares then it won't give the length of hypotenuse it would give the area of a square.

Hence, the correct answer is:

Option: D

7 0

3 years ago

To test the belief that sons are taller than their fathers, a student randomly selects 13 fathers who have adult male children.

KATRIN_1 [288]

Answer:

1) B. The differences are normally distributed or the sample size is large

C. The sample size mus be large

E. The sampling method results in an independent sample

2) The null hypothesis H₀: $\bar x_1$ = $\bar x_2$

The alternative hypothesis Hₐ: $\bar x_1$ < $\bar x_2$

Test statistic, t = -0.00693

p- value = 0.498

Do not reject Upper H₀ because, the P-value is greater than the level of significance. There is sufficient evidence to conclude that sons are the same height as their fathers at 0.10 level of significance

Step-by-step explanation:

1) B. The differences are normally distributed or the sample size is large

C. The sample size mus be large

E. The sampling method results in an independent sample

2) The null hypothesis H₀: $\bar x_1$ = $\bar x_2$

The alternative hypothesis Hₐ: $\bar x_1$ < $\bar x_2$

The test statistic for t test is;

$t=\dfrac{(\bar{x}_1-\bar{x}_2)}{\sqrt{\dfrac{s_{1}^{2} }{n_{1}}-\dfrac{s _{2}^{2}}{n_{2}}}}$

The mean

Height of Father, h₁, Height of Son h₂

72.4, 77.5

70.6, 74.1

73.1, 75.6

69.9, 71.7

69.4, 70.5

69.4, 69.9

68.1, 68.2

68.9, 68.2

70.5, 69.3

69.4, 67.7

69.5, 67

67.2, 63.7

70.4, 65.5

$\bar x_1$ = 69.6

s₁ = 1.58

$\bar x_2$ = 69.9

s₂ = 3.97

n₁ = 13

n₂ = 13

$t=\dfrac{(69.908-69.915)}{\sqrt{\dfrac{3.97^{2}}{13}-\dfrac{1.58^{2} }{13}}}$

(We reversed the values in the square root of the denominator therefore, the sign reversal)

t = -0.00693

p- value = 0.498 by graphing calculator function

P-value > α Therefore, we do not reject the null hypothesis

Do not reject Upper H₀ because, the P-value is greater than the level of significance. There is sufficient evidence to conclude that sons are the same height as their fathers at 0.10 lvel of significance

8 0

4 years ago