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Alja [10]
3 years ago
10

A bowler once measured that she can throw the bowling ball with a speed of 15miles/hour.If it takes 3 seconds from the ball to t

ravel from the beginning of the lane down to the pins,how far is this distance in feet?
Physics
1 answer:
Vinvika [58]3 years ago
8 0

The distance traveled by the ball in feet is 66 ft.

The given parameters;

  • speed of the ball, u = 15 miles/hour
  • time of motion of the ball, t = 3 seconds

1 mile = 5280 feet

1 hour = 3600 s

The speed of the ball in feet per second is calculated as follows;

v = \frac{15 \ miles}{hour} \times \frac{5280 \ ft}{1 \ mile} \times \frac{1 \ hour}{3600 \ s} = 22 \ ft/s

The distance traveled by the ball in feet is calculated as follows;

Distance = speed x time

Distance = 22 ft/s x 3 s

Distance = 66 ft

Thus, the distance traveled by the ball in feet is 66 ft.

Learn more here: brainly.com/question/13722298

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Answer:

3.125 m

Explanation:

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According to question

Horizontal force=F=f=\mu_kmg

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Horizontal force=F=0.2\times 11.2\times 9.8=21.95 N

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s=\frac{11.2\times (3.5)^2}{2\times 0.2\times 11.2\times 9.8}

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a toy car travels from A to B at constant speed 30km/hr and without stopping at B return A at constant speed v. if the average s
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Answer:

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