A bowler once measured that she can throw the bowling ball with a speed of 15miles/hour.If it takes 3 seconds from the ball to t
1 answer:
The distance traveled by the ball in feet is 66 ft.
The given parameters;
- speed of the ball, u = 15 miles/hour
- time of motion of the ball, t = 3 seconds
1 mile = 5280 feet
1 hour = 3600 s
The speed of the ball in feet per second is calculated as follows;
The distance traveled by the ball in feet is calculated as follows;
Distance = speed x time
Distance = 22 ft/s x 3 s
Distance = 66 ft
Thus, the distance traveled by the ball in feet is 66 ft.
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Answer:
Explanation:
The gravitational force exerted on the satellites is given by the Newton's Law of Universal Gravitation:
Where M is the mass of the earth, m is the mass of a satellite, R the radius of its orbit and G is the gravitational constant.
Also, we know that the centripetal force of an object describing a circular motion is given by:
Where m is the mass of the object, v is its speed and R is its distance to the center of the circle.
Then, since the gravitational force is the centripetal force in this case, we can equalize the two expressions and solve for v:
Finally, we plug in the values for G (6.67*10^-11Nm^2/kg^2), M (5.97*10^24kg) and R for each satellite. Take in account that R is the radius of the orbit, not the distance to the planet's surface. So and
(Since
). Then, we get:
In words, the orbital speed for satellite A is 7667m/s (a) and for satellite B is 7487m/s (b).