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Lesechka [4]
3 years ago
12

Describe an instance where you might use standard rounding. Describe an instance where you might use order of magnitude estimati

on.
Physics
1 answer:
fenix001 [56]3 years ago
5 0

Explanation:

  1. Without doing exact calculations, you can round the price of a bag of candy to $2 (rounding up is your safest bet, since it takes sales tax into consideration and gives you an estimate on the high side) and quickly determine that 3 bags of candy would be about $6 and 4 bags would be about $8.
  2. Order of magnitude is usually written as 10 to the nth power. The n represents the order of magnitude. If you raise a number by one order of magnitude, you are basically multiplying that number by 10. If you decrease a number by one order of magnitude, you are basically multiplying that number by 0.1

Hope you got the answer

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What is mean by the value of universal gravitional constant is 6.67×10^-11​
aev [14]

Answer:

According to the gravitational law of Isaac Newton, "the gravitational force between any two objects is proportional to the product of the objects’ masses and inversely proportional to the square of the separation between their centers".

Therefore gravitational constant is the proportionality constant used in Newton’s Law of Universal Gravitation, and is commonly denoted by G. It is expressed as:

                                                 F= Gm1m2/r2

Another scientist Cavendish was able to measure the gravitational force and the value of the proportionality constant. It is expressed as G = 6.673×10-11 N m2 kg-2.

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3 years ago
A 5.0-newton force could have perpendicular components of
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It can have many set of perpendicular component but the most important one is 3 AND 4

Explanation:

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3 years ago
A man pulls a 10 kg box at constant speed across the floor with a rope. The tension in the rope is 120 N at an angle of 30°.
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98n

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5 0
3 years ago
A sound wave with a power of 8.8 × 10–4 W leaves a speaker and passes through section A, which has an area of 5.0 m2. What is th
statuscvo [17]
The intensity of the sound wave is defined as the ratio between the power of the wave and the area through which the wave passes:
I= \frac{P}{A}
where
I is the intensity
P is the power
A is the area

If we use the data of the problem, P=8.8 \cdot 10^{-4}W and A=5.0 m^2, we find the intensity of the sound wave:
I= \frac{P}{A}= \frac{8.8 \cdot 10^{-4} W}{5.0 m^2}=1.76 \cdot 10^{-4} W/m^2
6 0
3 years ago
A current of 200 mA through a conductor converts 40 joules of electrical energy into heat in 30 second
Komok [63]

Answer:

V = 6.65 [volt]

Explanation:

First, we must calculate the power by means of the following equation, where the voltage is related to the energy produced or consumed in a given time.

P=E/t\\P = 40/30\\P = 1.33[s]

Using the power we can calculate the voltage, by means of the following equation that relates the voltage to the current.

P=V*I

where:

V = voltage [Volts]

I = current = 200 [mA] = 0.2 [A]

V = 1.33/0.2\\V = 6.65 [volt]

8 0
3 years ago
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