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1 year ago

Explain how you would find the volume of a regular-shaped cube in comparison to an irregular shaped object such as a rock.

Physics

1 answer:

Colt1911 [192]1 year ago

4 0

1. To obtain the volume of a regular-shaped cube, we simply use the formula.

2. To find the volume of an irregular shaped object, we simply use displace method

<h3>Volume of regular shape cube</h3>

The volume of a cube can be obtained by using the formula below:

Volume = Length × Width × Height

<h3>Volume of irregular object</h3>

The volume of irregular objects can be obtained by using displacement method as illustrated below:

Volume of water = 20 mL
Volume of water + stone = 25 mL
Volume of stone =?

Volume of stone = (Volume of water + stone) - (volume of water)

Volume of stone = 25 - 20

Volume of stone = 5 mL

Thus, we can see that the volume of regular objects can be obtained by using their formulas whereas, the volume of irregular objects can be obtained by using displacement method.

Learn more about volume of irregular shape:

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The parallel plates in a capacitor, with a plate area of 7.90 cm2 and an air-filled separation of 2.70 mm, are charged by a 7.90

s2008m [1.1K]

Answer:

A) 26V

Explanation:

(a) the potential difference between the plates

Initial capacitance can be calculated using below expresion

C1= A ε0/ d1

Where d1= distance between = 2.70 mm= 2.70× 10^-3 m

ε0= permittivity of space= 8.85× 10^-12 Fm^-1

A= area of the plate = 7.90 cm2 = 7.90 ×10^-4 m^2

If we substitute the values we

C1= A ε0/ d1

=( 7.90 ×10^-4 × 8.85× 10^-12 )/2.70× 10^-3

C1=2.589 ×10^-12 F= 2.59 pF

Initial charge can be determined using below expresion

q1= C1 × V1

V1=2.589 ×10^-12 F

V1= voltage=7.90 V

If we substitute we have

q1= 2.589 ×10^-12 × 7.90

q1= 20.45×10^-12C

20.45 pC

Final capacitance can be calculated as

C2= A ε0/ d2

d2=8.80 mm= /8.80× 10^-3

7.90 ×10^-4 × 8.85× 10^-12 )/8.80× 10^-3

C1=0.794 ×10^-12 F= 0.794 pF

Final charge= initial charge

q2=q1 (since the battery is disconnected)

q2=q1= 20.45 pC

Final potential difference

V2= q/C2

= 20.45/0.794

= 26V

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g An electric hot plate raises its own internal energy and the internal energy of a cup of water by 9000J, and there is at the s

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Answer:

11700j

Explanation:

add the two because the plate has to maintain the temp.

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Carol drops a stone in a mine shaft 122.5 metres deep.How

Verizon [17]

Answer:

T = 5.36 s

Explanation:

given,

depth of the mine shaft = 122.5 m

speed of the sound = 340 m/s

time taken = ?

time taken by the stone to reach at the bottom

using equation of motion

$s = u t + \dfrac{1}{2}gt^2$

initial speed , u = 0 m/s

$t = \sqrt{\dfrac{2s}{g}}$

$t = \sqrt{\dfrac{2\times 122.5}{9.8}}$

t = 5 s

time taken by the sound to travel

d =v x t

$t = \dfrac{d}{v}$

$t = \dfrac{122.5}{340}$

t = 0.36 s

total time taken for the sound to reach carol after dropping the stone

T = 5 + 0.36

T = 5.36 s

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ie(p=m×v)

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