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1 year ago

Explain how you would find the volume of a regular-shaped cube in comparison to an irregular shaped object such as a rock.

Physics

1 answer:

Colt1911 [192]1 year ago

4 0

1. To obtain the volume of a regular-shaped cube, we simply use the formula.

2. To find the volume of an irregular shaped object, we simply use displace method

<h3>Volume of regular shape cube</h3>

The volume of a cube can be obtained by using the formula below:

Volume = Length × Width × Height

<h3>Volume of irregular object</h3>

The volume of irregular objects can be obtained by using displacement method as illustrated below:

Volume of water = 20 mL
Volume of water + stone = 25 mL
Volume of stone =?

Volume of stone = (Volume of water + stone) - (volume of water)

Volume of stone = 25 - 20

Volume of stone = 5 mL

Thus, we can see that the volume of regular objects can be obtained by using their formulas whereas, the volume of irregular objects can be obtained by using displacement method.

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The centers of a 15 kg lead ball and a 90 g lead ball are separated by 11 cm. part a what gravitational force does each exert on

Black_prince [1.1K]

The gravitational force between the two objects is calculated through the equation,

F = Gm₁m₂/d²

where F is the gravitational force, G is constant (equal to 6.67 x 10^-11), m₁ and m₂ are masses in kg and d is distance is meters.

Substituting the known values,

F = (6.67 x 10^-11)(15 kg)(0.090 kg)/ (0.11 m)²

F = 7.441 x 10^-9 N

ANSWER: 7.441 x 10^-9 N

8 0

3 years ago

17. A 1350 g projectile is launched with a force of 150 N. The length of the firing arm is 1.25 m.

creativ13 [48]

a) The exit velocity of the projectile is 16.7 m/s

b) The maximum height achieved by the projectile is 14.2 m

c) The total time of flight is 3.40 s

d) The distance covered by the projectile is 46.5 m

Explanation:

We solve this first part of the problem by applying the work-energy theorem, which states that the work done on the projectile is equal to the gain in kinetic energy of the projectile. Mathematically:

$W=Fd = \frac{1}{2}mv^2-\frac{1}{2}mu^2=\Delta K$

where:

F = 150 N is the force applied

d = 1.25 m is the displacement of the projectile (the length of the firing arm)

m = 1350 g = 1.35 kg is the mass of the projectile

u = 0 is the initial velocity of the projectile

v is the exit velocity of the projectile

Solving for v, we find:

$v=\sqrt{\frac{2Fd}{m}}=\sqrt{\frac{2(150)(1.25)}{1.35}}=16.7 m/s$

Assuming the projectile is fired vertically upward, then the initial kinetic energy of the projectile as soon as he leaves the cannon is fully converted into gravitational potential energy as it reaches the top of its trajectory. So we can write:

$K_i = U_f$

$\frac{1}{2}mv^2=mgh$

where:

$K_i$ is the initial kinetic energy

$U_f$ is the final potential energy

m = 1350 g = 1.35 kg is the mass of the projectile

v = 16.7 m/s is the velocity at which the projectile leaves the cannon

$g=9.8 m/s^2$ is the acceleration of gravity

h is the maximum height reached by the projectile

And solving for h, we find

$h=\frac{v^2}{2g}=\frac{(16.7)^2}{2(9.8)}=14.2 m$

Assuming the projectile is launched vertically upward, then the total time of flight is twice the time it takes for reaching the maximum height. This time can be found by using the following suvat equation:

$v=u-gt$

where:

u = 16.7 m/s is the initial velocity

$g=9.8 m/s^2$ is the acceleration of gravity

t is the time

The projectile reaches the maximum height when the vertical velocity becomes zero, so when v = 0. Therefore, substituting,

$0=u-gt\\t=\frac{u}{g}=\frac{16.7}{9.8}=1.70 s$

So, the total time of flight is

$T=2t=2(1.70)=3.40 s$

The motion of a projectile consists of two independent motions:

- A uniform motion (constant velocity) along the horizontal direction

- A uniformly accelerated motion, with constant acceleration (acceleration of gravity) in the downward direction

First we have to analyze the vertical motion, to find the time of flight of the apple. We can do it by using the following suvat equation:

$s=u_y t+\frac{1}{2}at^2$

where

s = -27 m is the vertical displacement of the apple

$u_y=u sin \theta = (16.7)(sin 42^{\circ})=11.2 m/s$ is the initial vertical velocity

t is the time if flight

$a=g=-9.8 m/s^2$ is the acceleration of gravity

Substituting we have:

$-27=11.2t - 4.9t^2\\4.9t^2-11.2t+27=0$

which has two solutions:

t = -1.46 s (negative, we discarde)

t = 3.75 s (this is our solution)

Now we can analyze the horizontal motion: the projectile moves horizontally with a constant velocity of

$v_x = u cos \theta = (16.7)(cos 42^{\circ})=12.4 m/s$

So, the distance it covers during its fall is given by

$d=v_x t=(12.4)(3.75)=46.5 m$

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3 0

4 years ago

A sample of an unknown substance has a mass of 0.465 kg. if 3,000.0 j of heat is required to heat the substance from 50.0°c to 1

hammer [34]

The specific heat of the substance will be 0.129 J/g°C.

<h3>What is specific heat capacity?</h3>

The amount of heat required to increase a substance's temperature by one degree Celsius is known as specific heat capacity.

Similarly, heat capacity is the relationship between the amount of energy delivered to a substance and the increase in temperature that results.

The given data in the problem is;

Q is the amount of energy necessary to raise the temperature = 3,000.0 j

M is the mass= 0.465 kg.

Δt is the time it takes to raise the temperature.=50°c

s stands for specific heat capacity=?

Mathematically specific heat capacity is given by;

$\rm Q= MC \triangle t \\\\ C = \frac{Q}{M\triangle t} \\\\ C = \frac{3000}{0.465 \triangle 50} \\\\ C =129.0 J/Kg^0C \\\\ C= 0.129 J/g^0C$