Question

In trapezoid $WXYZ$, $\overline{XY} \parallel \overline{WZ}$, $\angle WXZ = 105^\circ$, $\angle W = 43^\circ$, and $\angle Y = 141^\circ$. Find $\angle YXZ$, in degrees.

Answer 1

Answer:

32 degrees

Step-by-step explanation:

The diagram of the problem is drawn and attached.

In Triangle WXZ

105+43+$\angle WZX$=180 (Sum of Angles in a Triangle)

148+$\angle WZX$=180

$\angle WZX$=180-148

$\angle WZX$=32 degrees

Since |XY|//|WZ| (parallel to)

$\angle WZX$=$\angle YXZ$ (Alternate Angles)

Therefore:

$\angle YXZ$=32 degrees