What are two different types of electromagnetic waves

Please complete it if you know the answer. "The active region of a transistor is for.........

zubka84 [21]

Answer:

the active region is bound by cutoff region and saturation or power dissipation region.

Explanation:

5 0

3 years ago

How much current will a 500 W vacuum cleaner draw if it has a resistance of 30Ω?

Strike441 [17]

Answer:

Electric current, I = 4.08 A

Explanation:

We have,

Power of vacuum cleaner is 500 W

Resistance of vacuum cleaner is 30 ohms

It is required to find the current flowing through the vacuum cleaner. It can be calculated using the definition of power delivered. Its formula is given by :

$P=I^2R$

I is electric current

$I=\sqrt{\dfrac{P}{R}} \\\\I=\sqrt{\dfrac{500}{30}} \\\\I=4.08\ A$

So, the electric current flowing through the vacuum cleaner is 4.08 A.

3 0

3 years ago

PLEASE HELP BRANILIEST

frozen [14]

Answer: It’s Fiberglass

5 0

3 years ago

Read 2 more answers

Assume a beam with stirrups inclined at 60o angle with respect to the longitudinal steel resisting cracks developing at 45o angl

arlik [135]

Answer:

Shear resistance of a inclined stirrup is given by

Vᵇ = Asb(0.95*Fy)(cos α - sin α*cotβ) ((d-d')/sᵇ)

Explanation:

The shear resistance is checked in accordance with BS8110: Part 1, section 3.5.5. Shear resistance of a inclined stirrup is given by

Vᵇ = Asb(0.95*Fy)(cos α - sin α*cotβ) ((d-d')/sᵇ)

where,

Vᵇ=design shear resistance of inclined bars

Asb=cros-sectional area of the inclined bars

Fy=characteristics strength of the stirrups

α=angle between the inclined bars and the axis of the beam

β=angle between the compression strut of inclined bars and the axis of the beam

sᵇ=spacing of the inclined bars

d= effective depth and d'=effective depth minus cover to reinforcement

The shear stress is given by

v=V/bd

where V is the shear force due to ultimate loads. If v is shear stress

5 0

3 years ago

Let r denote the distance between the center of the earth and the center of the moon. What is the magnitude of the acceleration

stepan [7]

Answer:

The magnitude of the acceleration ae of the earth due to the gravitational pull of the moon is $\mathbf{3.3187\times10^{-5}}\frac{m}{s^{2}}$

Explanation:

By Newton's gravitational law, the magnitude of the gravitational force between two objects is:

$F=G\frac{Mm}{r^{2}}$ (1)

With G the gravitational constant, M the mass of earth, m the mass of the moon and r the distance between the moon and the earth, a quick search on physics books or internet websites give us the values:

$M=5.972\times10^{24}\,kg$