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gizmo_the_mogwai [7]
3 years ago
10

A student was producing 75 watts of power while applying a constant force of 225 newtons to slide a box of books 2.0 meters acro

ss the floor. How long did it take the student to slide the box of books?
Physics
1 answer:
oksano4ka [1.4K]3 years ago
8 0

Answer:

time taken = 6 secs

Explanation:

Power (P) = Force(F) * displacement(d)/ TIME (t)

    75= 225 * 2.0/t

t= 225*2/75

t= 6 sec

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Find the resistance of an electric light bulb if a current of 0.08 A flows when the potential difference across the bulb is 120
lora16 [44]
U=RI Ohm's law
then R=U/I
=120/0.08
=2250Ω
hope this helps you
8 0
3 years ago
How many butter, which has a usable energy content of 6.0 Cal/g (= 6000 cal/g), would be equivalent to the change in gravitation
Mazyrski [523]

Answer:

175.96 g

Explanation:

Potential energy required for the man to climb 7.07 km = m g h.

= 64 x 9.8 x 7070

= 4.434 x 10⁶ J

= 4.434 X 10⁶ / 4.2 cals

= 1.0557 x 10⁶ cals

= 1.0557 x 10⁶ / 6000 g of butter

= 175.96 g of butter.

3 0
2 years ago
A small sandbag is dropped from rest from a hovering hot-air balloon. (assume the positive direction is upward.) (a) after 1.5 s
marishachu [46]

solution:

We know v0 = 0, a = 9.8, t = 4.0. We need to solve for v

so,

we use the equation:

v = v0 + at

v = 0 + 9.8*4.0

v = 39.2 m/s

Now we just need to solve for d, so we use the equation:

d = v0t + 1/2*a*t^2

d = 0*4.0 + 1/2*9.8*4.0^2

d = 78.4 m

3 0
3 years ago
To practice Problem-Solving Strategy 7.2 Problems Using Mechanical Energy II. The Great Sandini is a 60.0-kg circus performer wh
sp2606 [1]

Answer:

v = 15.45 m/s

Explanation:

As per mechanical energy conservation we can say that here since friction is present in the barrel so we will have

Work done by friction force = Loss in mechanical energy

so we will have

W_f = (U_i + K_i) - (U_f + K_f)

here we know that

W_f = F_f . d

W_f = 40 \times 4

W_f = 160 J

Initial compression in the spring is given as

F = kx

4400 = 1100 x

x = 4 m

now from above equation

W_f = (\frac{1}{2}kx^2 + 0) - (mgh + \frac{1}{2}mv^2)

160 = (\frac{1}{2}1100(4^2) + 0) - (60 \times 9.8\times 2.50 + \frac{1}{2}(60)v^2)

160 = 8800 - 1470 - 30 v^2

v = 15.45 m/s

3 0
3 years ago
Consider eight,eight-cubic centimeter (8 cm3) sugar cubes stacked so that they form a single 2 x 2 x 2 cube. How does the surfac
In-s [12.5K]
To find the surface area of a single cube we first nees to take the cube root of 8cm3 which is 2.

Now we know that the length of each side is 2 and we can find the area of one side by doing 2x2 which is 4.

To find the total surface area of one cube we do 4 times 6 side giving us a total of 24cm2.

To find the total surface area of the 8 individual cubes, we multiply 24cm2 by 8 to give us a total of 192cm2.

Now to find the total surface area of the one large cube, we know that each side of one of the small cubes is 4cm2 and the large cube is set up so that there are two levels of four cubes right on top of each other. So, the total area of each side of the large cube is 4cm2 times 4 which gives us 16cm2.

Then we multiply 16cm2 by 6 sides to give us a total surface area of 96cm2.

The ratio of the surface area of the single large cube comapred to the total surface area of the single cubes is 96:192

We can further simplify this ratio:

96:192

48:96

24:48

12:24

6:12

3:6

1:2
5 0
3 years ago
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