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gizmo_the_mogwai [7]
3 years ago
10

A student was producing 75 watts of power while applying a constant force of 225 newtons to slide a box of books 2.0 meters acro

ss the floor. How long did it take the student to slide the box of books?
Physics
1 answer:
oksano4ka [1.4K]3 years ago
8 0

Answer:

time taken = 6 secs

Explanation:

Power (P) = Force(F) * displacement(d)/ TIME (t)

    75= 225 * 2.0/t

t= 225*2/75

t= 6 sec

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A pendulum with a length of 1 meter is released from an initial angle of 15.0° after 1000s its amplitude has been reduced by fri
Setler [38]

Answer:

0.366×10^{-3} / s

Explanation:

θ = θmax e^{-bt/2m}

Given that

             θ = 5.50°

             θmax = 15.0°

So that we have

                ln (θ / θmax) = -bt /2m

            = - ln(5.50°/ 15.0°) / 1000s = b /2m

             = b / 2m = 0.366×10^{-3} / s

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7. What can be done to prevent such devastating destruction as seen in the earthquake in Haiti? correct me if im wrong on the su
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3 0
3 years ago
Heptane and water do not mix, and heptane has a lower density (0.684 g/mL) than water (1.00 g/mL). A graduated cylinder contains
lakkis [162]

Given that the density of heptane is

d_h=\frac{0.684g}{mL}

The mass of heptane is

m_h=31\text{ g}

The density of water is

d_w=\frac{1g}{mL}

The mass of water is

m_w=37\text{ g}

The volume of heptane will be

\begin{gathered} V_h=\frac{m_h}{d_h} \\ =\frac{31}{0.684} \\ =45.32\text{ mL} \end{gathered}

The volume of water will be

\begin{gathered} V_w=\frac{m_w}{d_w} \\ =\frac{37}{1} \\ =37\text{ mL} \end{gathered}

Thus, the volume of heptane is 45.32 mL and the volume of water is 37 mL.

The total volume of liquid in the cylinder will be

\begin{gathered} V=V_h+V_w \\ =45.32+37 \\ =82.32\text{ mL} \end{gathered}

The total volume of liquid in the cylinder will be 82.32 mL.

7 0
1 year ago
. Friction is a rubbing force that ___________ a spinning yo-yo.
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The yo-yo speeds up when you rub it
3 0
3 years ago
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Explain how the basic unit are combined to give the derived units of force, velocity, pressure and work
LuckyWell [14K]

Velocity:

Velocity is change in displacement with respect to time:

\frac{\Delta x}{\Delta t}

Analysing the units, meters (displacement) and seconds (time) are basic units:

\frac{m}{s}

Therefore the unit of velocity is m/s

Force:

Newton's second law of motion:

F = ma

Kilogram (mass) is a basic unit, and accelerations unit can be found using the equation:

a=\frac{\Delta v}{\Delta t}

Analysing the units:

\frac{\frac{m}{s}}{s}=\frac{m}{s^2}

Therefore, the unit of force is:

kg\frac{m}{s^2}

Pressure:

Pressure is given by the equation:

P=\frac{F}{S} where S is area of effect, F is force

Area for a basic rectangle (geometric shape is arbitrary for dimensional analysis) is found by multiplying two lengths:

[l^2]=m^2, the unit of area

Dividing the aforementioned unit of force by the unit of area:

\frac{kg\frac{m}{s^2}}{m^2}=\frac{kg}{ms^2}, the unit of pressure

Work:

Work is given by the equation:

W=\vec{F}\cdot \vec{x}, (dot product may be assumed as normal multiplication for the purposes of unit analysis)

Knowing displacement's (x) unit is m:

[W]=\frac{kgm}{s^2}m=\frac{kgm^2}{s^2}, the unit of work.

3 0
3 years ago
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