How do I solve this. Log 5x = log (2x+9)

1 answer:

3 0

$D:5x\ \textgreater \ 0 \wedge 2x+9\ \textgreater \ 0\\
D:x\ \textgreater \ 0 \wedge 2x\ \textgreater \ -9\\
D:x\ \textgreater \ 0 \wedge x\ \textgreater \ -\dfrac{9}{2}\\
D:x\ \textgreater \ 0\\\\
\log5x=\log(2x+9)\\
5x=2x+9\\
3x=9\\
x=3$

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Step-by-step explanation:

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Assume that the population of human body temperatures has a mean of 98.6 degrees F and a standard deviation of 0.62 degrees F. I

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Answer:

0% probability of getting a mean temperature of 98.2 degrees F or lower.

Step-by-step explanation:

The Central Limit Theorem estabilishes that, for a random variable X, with mean $\mu$ and standard deviation $\sigma$ , a large sample size can be approximated to a normal distribution with mean $\mu$ and standard deviation $\frac{\sigma}{\sqrt{n}}$ .

Normal probability distribution

Problems of normally distributed samples can be solved using the z-score formula.

In a set with mean $\mu$ and standard deviation $\sigma$ , the zscore of a measure X is given by:

$Z = \frac{X - \mu}{\sigma}$

The Z-score measures how many standard deviations the measure is from the mean. After finding the Z-score, we look at the z-score table and find the p-value associated with this z-score. This p-value is the probability that the value of the measure is smaller than X, that is, the percentile of X. Subtracting 1 by the pvalue, we get the probability that the value of the measure is greater than X.

In this problem, we have that:

$\mu = 98.6, \sigma = 0.62, n = 106, s = \frac{0.62}{\sqrt{106}} = 0.06$