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Fed [463]
3 years ago
8

How do I solve this. Log 5x = log (2x+9)

Mathematics
1 answer:
liubo4ka [24]3 years ago
3 0
D:5x\ \textgreater \ 0 \wedge 2x+9\ \textgreater \ 0\\
D:x\ \textgreater \ 0 \wedge 2x\ \textgreater \ -9\\
D:x\ \textgreater \ 0 \wedge x\ \textgreater \ -\dfrac{9}{2}\\
D:x\ \textgreater \ 0\\\\
\log5x=\log(2x+9)\\
5x=2x+9\\
3x=9\\
x=3
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Step-by-step explanation:

For the given problem:

Let the balances of the saving accounts be (x) and (y)

Leah has two savings accounts with balances totaling $8,000

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x+y=8000 (1)

She withdrew 15% from one and 40% from the other. If she has $6,350 remaining in the accounts

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that will give the decimals: 0.85 and 0.6

so, we can write the following equation:

0.85x+0.6y=6350 (2)

Now, solve the equations (1) and (2) to find (x) and (y)

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y=8000-x (3)

Substitute with (y) from equation (3) into equation (2)

0.85x+0.6*(8000)-x =6350

Now solve the equation

0.85x+0.6*8000-0.6x=6350

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and the smaller account = y = 1800



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