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3 years ago

How do I solve this. Log 5x = log (2x+9)

1 answer:

3 0

$D:5x\ \textgreater \ 0 \wedge 2x+9\ \textgreater \ 0\\
D:x\ \textgreater \ 0 \wedge 2x\ \textgreater \ -9\\
D:x\ \textgreater \ 0 \wedge x\ \textgreater \ -\dfrac{9}{2}\\
D:x\ \textgreater \ 0\\\\
\log5x=\log(2x+9)\\
5x=2x+9\\
3x=9\\
x=3$

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Answer:

$N(t) = 37.1(1.38)^t$

Step-by-step explanation:

Exponential function:

An exponential function has the following format:

$N(t) = N(0)(1+r)^t$

In which N(0) is the initial value and r is the rate of change, as a decimal.

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3 years ago

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Step-by-step explanation:

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Add 3/2 to each side

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-3/2 = b

y= 1/2x-3/2

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