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andrezito [222]
3 years ago
9

The sum of 3 times a number and 7

Mathematics
1 answer:
leva [86]3 years ago
7 0
Algebraically, that will be expressed as:

3n +7
You might be interested in
Factor 3/4 out of 3/4z + 6
Alenkasestr [34]
ANSWER

\frac{3}{4} z + 6 =  \frac{3}{4} (z +  8  )


EXPLANATION

We want to factor
\frac{3}{4}
out of

\frac{3}{4} z + 6

The first term is already having a factor of
\frac{3}{4}
The constant term which is the second term is not having a factor of
\frac{3}{4}
so we need to use a trick of multiplying and dividing by the same factor to obtain,



\frac{3}{4} z + 6 =  \frac{3}{4} z +  \frac{3}{4}  \times  \frac{6}{ \frac{3}{4} }


We can now factor
\frac{3}{4}
out of the right hand side to obtain,

\frac{3}{4} z + 6 =  \frac{3}{4} (z +  \frac{6}{ \frac{3}{4} } )
Let us rewrite the right most fraction using the normal division symbol.

\frac{3}{4} z + 6 =  \frac{3}{4} (z +  6 \div  \frac{3}{4}  )




We simplify to obtain,

\frac{3}{4} z + 6 =  \frac{3}{4} (z +  6  \times  \frac{4}{3}  )



This further gives us,


\frac{3}{4} z + 6 =  \frac{3}{4} (z +  2 \times  4  )



\frac{3}{4} z + 6 =  \frac{3}{4} (z +  8  )


5 0
3 years ago
Read 2 more answers
How many solutions can be found for the equation −4x − 11 = 2(x − 3x) + 13?
AveGali [126]
The answer is No solution
7 0
2 years ago
Read 2 more answers
Jason can paint a wall in 20 minutes. Leah can paint the same wall in 10 minutes.
Vilka [71]

Answer:

There is no solution to this answer.

Step-by-step explanation:

Leah's rate is 10x

Jason's rate is 20x

If you solve for 20x=10x, you get no solution. They are parallel lines.

8 0
3 years ago
Find the surface area of the prism. 4 cm 3 cm 5 cm 9 cm
iren [92.7K]

Answer:

540cm^3

Step-by-step explanation:

4*3*5*9=12*5*9=60*9=540

8 0
3 years ago
Read 2 more answers
X²+y²-6x+14y-1=0<br> and please show your work so I can learn
Eva8 [605]

Hello there,

I hope you and your family are staying safe and healthy during this winter season.

x^2 + y^2 -6x+14y-1=0

We need to use the Quadratic Formula*

x =\frac{-b+\sqrt{b^2}-4ac }{2a} , \frac{-b-\sqrt{b^2} -4ac }{2a}

Thus, given the problem:

a = 1, b=-6, c=y^2+14y-1

So now we just need to plug them in the Quadratic Formula*

x=\frac{6+2\sqrt{(-6)^2-4(y^2+14y-1)} }{2} , x=\frac{6-\sqrt{(-6)^2-4(y^2+14y-1)} }{2}

As you can see, it is a mess right now. Therefore, we need to simplify it

x=\frac{6+2\sqrt{10-y^2-14y} }{2}, x = \frac{6-2\sqrt{10-y^2-14y} }{2}

Now that's get us to the final solution:

x=3+\sqrt{10-y^2-14y}, x=3-\sqrt{10-y^2-14y}

It is my pleasure to help students like you! If you have additional questions, please let me know.

Take care!

~Garebear

3 0
2 years ago
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