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boyakko [2]
4 years ago
9

Calculate the distance between (5, 3) and (-1, 6). Round your answer to the nearest tenth if necessary. (One place after the dec

imal)
Mathematics
1 answer:
rusak2 [61]4 years ago
6 0

Answer:

{xy}^{2}  =  {6}^{2}  +  {3}^{2}  =45 \\ xy =  \sqrt{45}  = 6.71

sorry but I am not sure if this is right :(

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so a group of students are in a club. half are boys ,4/9 of the boys have brown eyes. how many boys have brown eyes?
aliina [53]
it will have to be 5/9 or0.5555555556
8 0
4 years ago
One alloy is 2 parts iron to 3 parts silver and another alloy is 7 parts iron to 3 parts silver. How much of each should be comb
Shalnov [3]
Let x be your first alloy
2/5x+7/10(30-x)=1/2(30)
4x+210-7x=150
3x=60
x=20
So, you need 20 lbs of the first alloy, and 10 parts of the second to make 30 lbs of half iron and half silver alloy!
8 0
4 years ago
What linear equation in slope intercept form does this graph represent?
guajiro [1.7K]

Answer: Hope this helps

y = 3/5x + 100

Slope: 3/5

Y-int: 100

Step-by-step explanation:

y = mx + b

<em>replace b with y-int</em>

y = mx + 100

<em>replace m with the slope which is 3/5</em>

y = 3/5x + 100

<em>How do you get slope?</em>

<em>Well I did rise/run with two points so I saw it ran 5 squares and rose only 3.</em>

<em>How do you get the y-int?</em>

<em>Well the y-int is the point where x is 0. So using the point (0,100), since x is 0, the y-int is 100.</em>

6 0
2 years ago
Why would using a net and needing to know how to calculate surface area be an important part of designing a three-dimensional ob
son4ous [18]

Answer:

A net is a pattern made when the surface of a three-dimensional figure or solid is laid out flat showing each face of the figure. It is then possible to use the net to calculate the surface area of the solid. Surface Area of a Cube using Nets. A cube is a three-dimensional figure with six matching square faces.

Step-by-step explanation:

hope it helps

4 0
4 years ago
What is the first derivative of r with respect to t (i.e., differentiate r with respect to t)? r = 5/(t2)Note: Use ^ to show exp
adelina 88 [10]

Answer:

The first derivative of r(t) = 5\cdot t^{-2} (r(t)=5*t^{-2}) with respect to t is r'(t) = -10\cdot t^{-3} (r'(t) = -10*t^{-3}).

Step-by-step explanation:

Let be r(t) = \frac{5}{t^{2}}, which can be rewritten as r(t) = 5\cdot t^{-2}. The rule of differentiation for a potential function multiplied by a constant is:

\frac{d}{dt}(c \cdot t^{n}) = n\cdot c \cdot t^{n-1}, \forall \,n\neq 0

Then,

r'(t) = (-2)\cdot 5\cdot t^{-3}

r'(t) = -10\cdot t^{-3} (r'(t) = -10*t^{-3})

The first derivative of r(t) = 5\cdot t^{-2} (r(t)=5*t^{-2}) with respect to t is r'(t) = -10\cdot t^{-3} (r'(t) = -10*t^{-3}).

5 0
3 years ago
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