Step-by-step explanation:
Putting both functions into a graphing calculator, we can easily find the domain and range. (attatched)
By looking at the graph, we can tell that f(x) is a quadratic function because of the symmetry. We can also tell that it never goes below 4. Knowing this, we can determine the domain and range.
Domain: {x | all real numbers}
Range: {y | y > 4}
By looking at the graph, we can tell that g(x) is an exponential function because it has a curve, and never goes below the x. Knowing this, we can determine the domain and range.
Domain: {x | all real numbers}
Range: {y | y > 0}
This revolves around exact trig values - no easy way to say this, you just need to memorise them. They are there for sin cos and tan, but I will give you the main tan ones below - note this is RADIANS (always work in them when you can, everything is better):
tan0: 0
tanpi/6: 1/sqrt(3)
tanpi/4: 1
tanpi/3: sqrt(3)
tanpi/2: undefined
Now we just need to equate -2pi/3 to something we understand. 2pi/3 is 1/3 of the way round a circle, so -2pi/3 is 1/3 of the way round the circle going backwards (anticlockwise), so on a diagram we already know it's in the third quadrant of the circle (somewhere between pi and 3pi/2 rads).
We also know it is pi/3 away from pi, so we are looking at sqrt(3) or -sqrt(3) because of those exact values.
Now we just need to work out if it's positive or negative. You can look up a graph of tan and it'll show that the graph intercepts y at (0,0) and has a period of pi rads. Therefore between pi and 3pi/2 rads, the values of tan are positive. Therefore, this gives us our answer of sqrt(3).
Answer:
2 is the LCF :)
Step-by-step explanation:
All are divisible by 2. 2 is the lowest number than even numbers can be divided by.
Answer:
Quadrilateral A has side lengths 2, 3, 5, and 6. Quadrilateral B has side lengths 4, 5, 8, and 10. Could one of the quadrilaterals be a scaled copy of the other ...
Answer:
if f(x) = 3x+4, the rate of change is 4.
if f(x) = 2x+7, the rate of change is 2.
Step-by-step explanation:
We know that the average rate of change over the interval x=0 to x=8 is:
(f(x2) - f(x1))/x2-x1
Where:
x2 = 8
x1 = 0
if f(x) = 3x+4
so f(8)=3(8)+4 = 28
f(0)=3(0)+4 = 4
Then: (f(x2) - f(x1))/x2-x1 = (28 - 4)/8-0 = 24/8 = 3
On the other hand, if f(x) = 2x+7
f(8) = 2(8)+7 = 23
f(0) = 2(0)+7 = 7
Then: (f(x2) - f(x1))/x2-x1 = Then: 23 - 7/8-0 = 16/8 = 2
