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kenny6666 [7]
3 years ago
9

As important as it is to plan ahead,sometimes you

Physics
2 answers:
Natali5045456 [20]3 years ago
5 0

Answer:

B. Cant stop things from going wrong.

Explanation:

To me it's the only reasonable answer...

fiasKO [112]3 years ago
3 0
Can’t stop from things going a different way than how you plan it to be.
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Thiết bị trao đổi nhiệt ngược chiều, nhiệt độ chất lỏng nóng vào là 310°C, ra là 115°c. Nhiệt độ chất lỏng lạnh vào là 25°c và r
Vika [28.1K]

Answer: 129.5 m

Explanation:

310 + 115 + 25 + 68 = 518

518 / 4 = 129.5 m

i think. Sorry if this is wrong

:)

5 0
3 years ago
In Thomson experiment, why was the glowing beam repelled by a negatively charged plate
algol13
<span>In Thomson experiment, why was the glowing beam repelled by a negatively charged plate, because the glowing beam was negatively charged. The glowing beam particles were attracted to the positive plate.

</span><span>J.JThomson proved that the cathode rays produced a stream of negatively charged particles called electrons. </span>
6 0
3 years ago
Read 2 more answers
An airplane traveling at half the speed of sound emits a sound of frequency 4.68 kHz. (a) At what frequency does a stationary li
kkurt [141]

Answer:

(a) 9.36 kHz

(b) 3.12 kHz

Explanation:

(a)

V = speed of sound

v = speed of airplane = (0.5) V

f = actual frequency of sound emitted by airplane = 4.68 kHz = 4680 Hz

f' = Frequency heard by the stationary listener

Using Doppler's effect

f' = \frac{Vf}{V-v}

f' = \frac{V(4680)}{V-(0.5)V)}

f' = 9360 Hz

f' = 9.36 kHz

(b)

V = speed of sound

v = speed of airplane = (0.5) V

f = actual frequency of sound emitted by airplane = 4.68 kHz = 4680 Hz

f' = Frequency heard by the stationary listener

Using Doppler's effect

f' = \frac{Vf}{V+v}

f' = \frac{V(4680)}{V+(0.5)V)}

f' = 3120 Hz

f' = 3.12 kHz

6 0
4 years ago
How do you find the amplitude of a wave?
Sergio039 [100]

Answer:

To find the amplitude, wavelength, period, and frequency of a sinusoidal wave, write down the wave function in the form y(x,t)=Asin(kx−ωt+ϕ).

The amplitude can be read straight from the equation and is equal to A.

The period of the wave can be derived from the angular frequency (T=2πω).

6 0
2 years ago
Read 2 more answers
A 0.40-kg mass attached to the end of a string swings in a vertical circle having a radius of 1.8 m. At an instant when the stri
enyata [817]

Answer:

T=8.1N

Explanation:

From the question we are told that:

Mass m=0.40

Radius r=1.8m

Angle Beneath the Horizontal \theta =40 \textdegree

Speed v=5.0m/s

The Tension Angle

 \alpha=90-\theta\\\\\alpha=90-40

 \alpha=50 \textdegree

Generally the equation for Tension is is mathematically given by

 T=\frac{mv^2}{r}+mgcos \alpha

 T=\frac{0.40*5^2}{1.8}+0.40*5cos50

 T=8.1N

7 0
3 years ago
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