Answer:
a) Vin(r,θ)=(-Vo/3)+(4Vo/3R^2)r^2P2cosθ
b)σ(θ)=((Voεo)/3R)(20P2cosθ-1)
Explanation:
Due to the complex variables used to solve this exercise, the solution and the explanation are in the image
Answer:
Explanation:
To solve this problem we have to take into account that the energy consumed per second is the power. Hence, by multipling the power and the time spent to arrive to the lab we obtain the total energy consumed.
But first we have to calculate the time

Now we use E=W*t for both times

A. Hence, by running the energy consumed is lower.
B.
E1=1008000J
E2=1392000J
C. Because the more intense exercise is made in a lower time in comparison with the less intense exercise, and higher the time, more energy is consumed.
12km = 12000m
12000m / 4 m/s = 3000s
just under one hour
Answer:
distance - meters
speed - meters/seconds
time - seconds
velocity - meters/seconds
acceleration - meters/seconds²