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3 years ago

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What are the three key points to seismic waves

1 answer:

leonid [27]3 years ago

6 0

Earthquakes produce three types of seismic waves: primary waves, secondary waves, and surface waves. Each type moves through materials differently. In addition, the waves can reflect, or bounce, off boundaries between different layers.

three key points:

1. they all change the earth by shifting plates in different ways.

2. these waves lead to our plates form today, which are always changing.

3. even the smallest earthquakes make the slightest changes to our ground. and many happen in just a day! we just never feel it.

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As soon as parachute of a falling soldier opens, how will the accleration change?

WITCHER [35]

Answer:

The acceleration will become zero

Explanation:

When the parachute of a falling soldier is opened the wide surface area decreases his velocity. This also translates to the drag force acting on the fallen soldier

The acceleration will become zero when the velocity of the fallen soldier is constant. This principle is the reason the parachute is used for safety reasons .

6 0

3 years ago

Atoms in a solid are not stationary, but vibrate about their equilibrium positions. Typically, the frequency of vibration is abo

hoa [83]

To develop this problem it is necessary to use the equations of description of the simple harmonic movement in which the acceleration and angular velocity are expressed as a function of the Amplitude.

Our values are given as

$f = 4.11 *10^{12} Hz$

$A = 1.23 * 10^{-11}m$

The angular velocity of a body can be described as a function of frequency as

$\omega = 2\pi f$

$\omega = 2\pi 4.11 *10^{12}$

$\omega=2.582*10^{13} rad/s$

PART A) The expression for the maximum angular velocity is given by the amplitude so that

$V = A\omega$

$V =( 1.23 * 10^{-11})(2.582*10^{13})$

$V = = 317.586m/s$

PART B) The maximum acceleration on your part would be given by the expression

$a = A \omega^2$

$a =( 1.23 * 10^{-11})(2.582*10^{13})^2$

$a= 8.2*10^{15}m/s^2$

4 0

4 years ago

A first-order reaction has a rate constant of 0.241/min. if the initial concentration of a is 0.859 m, what is the concentration

nordsb [41]

Answer: 0.077 M

Explanation:

Expression for rate law for first order kinetics is given by:

$k=\frac{2.303}{t}\log\frac{a}{a-x}$

where,

k = rate constant = $0.241minute^{-1}$

t = time taken for decay process = 10 minutes

a = initial amount of the reactant= 0.859 M

a - x = amount left after decay process =?

Putting values in above equation, we get:

$0.241 minutes^{-1}=\frac{2.303}{10.0}\log\frac{0.859}{a-x}$

$(a-x)=0.077M$

Thus the concentration of a after 10.0 minutes is 0.077 M.

5 0

3 years ago

Read 2 more answers

Which product of alcoholic fermentation causes dough to rise and creates the little holes in bread? A. water B. oxygen C. glucos

lbvjy [14]

Answer:

Carbon Dioxide

Explanation:

4 0

4 years ago

An 877 kg drag race car accelerates from rest to 116 km/h in 0.951 s. What change in momentum does the force produce? Answer in

Eduardwww [97]

Answer:

The change in momentum is 28265.71 kg-m/s.

Explanation:

Given that,

Mass of a car, m = 877 kg

Initial velocity of the car, u = 0 (at rest)

Final velocity of the car, v = 116 km/h = 32.23 m/s

Time, t = 0.951 s

We need to find the change in momentum produced by the force. It can be calculated as the difference of final momentum and the initial momentum.

$\Delta P=m(v-u)\\\\=877\times (32.23-0)\\\\=28265.71\ kg-m/s$

So, the change in momentum is 28265.71 kg-m/s.

7 0

3 years ago