3(j+4)-9=9
3j + 12 -9 =9
3j +3 =9
3j =6
j=2
Answer:
The probability that a student earns a grade of A is 1/7.
Let E be an event and S be the sample space. The probability of E, denoted by P(E) could be computed as:
P(E) = n(E) / n(S)
As the total number of students = n(S) = 35
Students getting the grade A = n(E) = 5
So, the probability that a student earns a grade of A:
P(E) = n(E) / n(S)
= 5/35
= 1/7
Hence, the probability that a student earns a grade of A is 1/7.
Keywords: probability, sample space, event
The formula for a cone is

insert 20 for your height and rearrange the formula to find the radius. Leave a comment if you need more help.
32a) the same six numbers are reported in the same order but at different starting points
b) All have sum of 999
c) yes, it is the same. 5/13=0.384615
384+615=999
Here we know that the initial velocity of the car is given by:

And the final velocity of the car is given by:

It took 3 seconds to attain the final velocity, so we have 
Therefore, the acceleration can be obtained by:


Plugging the values of the initial, final velocity and the time, we get:

So the acceleration of the car is given by:

Now we need to find the direction of the average acceleration of the car:

Here, x and y are the coefficients of the 'x' and 'y' components of the vector:

Therefore, the direction of the average acceleration of the car is
.