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3 years ago

0.8h=112 solve for h

Mathematics

1 answer:

madreJ [45]3 years ago

8 0

Answer:

h = 140

Step-by-step explanation:

To solve for h, we will have to get the equation into the form h = _. That would be our answer.

0.8h = 112

Divide 0.8 from both sides to get rid of the coefficient of 0.8 on the left side.

h = 112/0.8

Change 112/0.8 to 1120/8 on the right side. This will make the fraction easier to simplify.

h = 1120/8

Simplify the fraction on the right side.

h = 140/1

140/2 equals 140.

h = 140

I hope you find this helpful. :)

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Let A be the set of all lines in the plane. Define a relation R on A as follows. For every l1 and l2 in A, l1 R l2 ⇔ l1 is paral

Lyrx [107]

Answer:

Hence, the relation R is a reflexive, symmetric and transitive relation.

Given :

A be the set of all lines in the plane and R is a relation on set A.

$R=\{l_1,l_2\in A|l_1 \;\text{is parallel to}\; l_2\}$

To find :

Which type of relation R on set A.

Explanation :

A relation R on a set A is called reflexive relation if every $a\in A$ then $(a,a)\in R$ .

So, the relation R is a reflexive relation because a line always parallels to itself.

A relation R on a set A is called Symmetric relation if $(a,b)\in R$ then $(b,a)\in R$ for all $a,b\in A$ .

So, the relation R is a symmetric relation because if a line $l_1$ is parallel to the line $l_2$ the always the line $l_2$ is parallel to the line $l_1$ .

A relation R on a set A is called transitive relation if $(a,b)\in R$ and $(b,c)\in R$ then $(a,c)\in R$ for all $a,b,c\in A$ .

So, the relation R is a transitive relation because if a line $l_1$ s parallel to the line $l_2$ and the line $l_2$ is parallel to the line $l_3$ then the always line $l_1$ is parallel to the line $l_3$ .

Therefore the relation R is a reflexive, symmetric and transitive relation.

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Tell which equation you would use to isolate a variable in order to solve the system using substitution. Explain your reasoning.

vampirchik [111]

2x+y=-10
Multiply both side by 3
2x*3+y*3=-10*3
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3x-y=0
Multiply both side by 2
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Next, use substitute property
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Substitute y with -30
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Add 30 to each side
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Then, I would use equation 3x+1.5y=-15 in this question by multiply 2x+y=-10 by multiplying both side by 3/2 to eliminate x and to solve variables for y. Hope it help!

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