-3.25 (5 continues forever) ○ -3.2 (2 continues forever) Greater than or less than

A piece of copper has a mass of 58kg and displaces 5918ml. What is its density?

uranmaximum [27]

Answer:

8.96 g/cm2

Step-by-step explanation:

3 0

3 years ago

Mark is going to an awards dinner and wants to dress appropriately. He had one blue shirt, one white dress shirt, one black dres

lidiya [134]

Answer:

All the four statements are true , which are -

(A) The subset contains contains of all the outfits that have grey slacks .

(B) The subset contains contains of all the outfits that have grey slacks and red tie .

(C) The subset contains contains of all the outfits that have grey slacks and blue shirt .

(D) The subset contains contains of all the outfits that do not have black slacks .

Step-by-step explanation:

We are given with Outfit 2 , 4 and 6

Outfit 2 - Blue grey red

Outfit 4 - White grey red

Outfit 6 - Black grey red

(A) Since only 2,4, and 6 contain grey slacks, and no other outfit contains grey slacks, those are the subsets that contain grey slacks. Thus , this statement is true .

(B) Just outfits 2, 4, and 6 have grey slacks and a red tie, proving the statement. Other clothes do not include grey slacks and a red tie; they may include a red tie but not both grey slacks and a red tie. Hence , the statement is true .

(C) Since the outfit 2 has grey slacks and a blue shirt, the statement is correct; no other outfit has both grey slacks and a blue shirt. Therefore , this statement is also correct .

(D) The argument is correct since all of the subsets contain grey slacks and no black slacks.

Hence , all the options A , B , C , D are correct and describes the subset .

The given question is incomplete , the complete question is attached here -

3 0

3 years ago

PLEASE HELP !! ILL GIVE BRAINLIEST *EXTRA 40 POINTS* DONT SKIP :(( .!

Harrizon [31]

180-53 is 127 angle 6 and 3 would be the same so your answer is 127

3 0

3 years ago

Find derivative problem Find B’(6)

dalvyx [7]

Answer:

$B^\prime(6) \approx -28.17$

Step-by-step explanation:

We have:

$\displaystyle B(t)=24.6\sin(\frac{\pi t}{10})(8-t)$

And we want to find B’(6).

So, we will need to find B(t) first. To do so, we will take the derivative of both sides with respect to x. Hence:

$\displaystyle B^\prime(t)=\frac{d}{dt}[24.6\sin(\frac{\pi t}{10})(8-t)]$

We can move the constant outside:

$\displaystyle B^\prime(t)=24.6\frac{d}{dt}[\sin(\frac{\pi t}{10})(8-t)]$

Now, we will utilize the product rule. The product rule is:

$(uv)^\prime=u^\prime v+u v^\prime$

We will let:

$\displaystyle u=\sin(\frac{\pi t}{10})\text{ and } \\ \\ v=8-t$

Then:

$\displaystyle u^\prime=\frac{\pi}{10}\cos(\frac{\pi t}{10})\text{ and } \\ \\ v^\prime= -1$

(The derivative of u was determined using the chain rule.)

Then it follows that:

$\displaystyle \begin{aligned} B^\prime(t)&=24.6\frac{d}{dt}[\sin(\frac{\pi t}{10})(8-t)] \\ \\ &=24.6[(\frac{\pi}{10}\cos(\frac{\pi t}{10}))(8-t) - \sin(\frac{\pi t}{10})] \end{aligned}$

Therefore:

$\displaystyle B^\prime(6) =24.6[(\frac{\pi}{10}\cos(\frac{\pi (6)}{10}))(8-(6))- \sin(\frac{\pi (6)}{10})]$

By simplification:

$\displaystyle B^\prime(6)=24.6 [\frac{\pi}{10}\cos(\frac{3\pi}{5})(2)-\sin(\frac{3\pi}{5})] \approx -28.17$

So, the slope of the tangent line to the point (6, B(6)) is -28.17.

5 0

3 years ago

In percent, the “whole” is 100. What is the “whole” in decimal form?

tekilochka [14]

1. You divide by 100 to find the decimal version of any percentage, and do the opposite for vise versa

8 0

3 years ago

-3.25 (5 continues forever) ○ -3.2 (2 continues forever) Greater than or less than​

-3.25 (5 continues forever) ○ -3.2 (2 continues forever) Greater than or less than