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3 years ago

Explain dissolving, and express how boiling can reverse the process in the example of salt water

2 answers:

7 0

Solids, liquids, and gases can all dissolve.
Dissolving depends on the molecules of the substance doing thedissolving, called the solvent, and the molecules of the substance being dissolved, called the solute.
Dissolving is the process in which these molecules interact and attract each other to form a solution.

Arada [10]3 years ago

5 0

Answer:

The process of dissolving can be defined as the process by which the solute dissolves in the solvent.

Example; Dissolving salt in water and a homogeneous mixture of salt and water is prepared during this process.

Boiling can be defined as heating the substance upto a certain temperature where it starts boiling. The boiling temperature for water is 100 degree Celcius.

The boiling of salt solution will evaporate all the water from the solution and only salt will be left over. This is a reverse of dissolving.

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The naturally occurring radioactive decay series that begins with 23592U stops with formation of the stable 20782Pb nucleus. The

dsp73

Answer: There are 7 alpha-particle emissions and 4 beta-particle emissions involved in this series

Explanation:

Alpha Decay: In this process, a heavier nuclei decays into lighter nuclei by releasing alpha particle. The mass number is reduced by 4 units and atomic number is reduced by 2 units.

Beta Decay : It is a type of decay process, in which a proton gets converted to neutron and an electron. This is also known as -decay. In this the mass number remains same but the atomic number is increased by 1.

In radioactive decay the sum of atomic number or mass number of reactants must be equal to the sum of atomic number or mass number of products .

$_{92}^{235}\textrm{U}\rightarrow _{82}^{207}\textrm{Pb}+X_2^4\alpha+Y_{-1}^0e$

Thus for mass number : 235 = 207+4X

4X= 28

X = 7

Thus for atomic number : 92 = 82+2X-Y

2X- Y = 10

2(7) - Y= 10

14-10 = Y

Y= 4

$_{92}^{235}\textrm{U}\rightarrow _{82}^{207}\textrm{Pb}+7_2^4\alpha+4_{-1}^0e$

Thus there are 7 alpha-particle emissions and 4 beta-particle emissions involved in this series

3 0

3 years ago

Determine the number of 3s electrons in Na .

Scorpion4ik [409]

Answer:

Explanation:The atomic number of sodium is 11. That is, the number of electrons in sodium is 11. Therefore, a sodium atom will have two electrons in the first shell, eight in the 2nd orbit, and an electron in the 3rd shell.

3 0

2 years ago

Choose the element described by the following electron configuration.

nadezda [96]

Answer:

The answer to your question is Argon

Explanation:

Electron configuration given 1s² 2s² 2p⁶ 3s² 3p⁶

To find the element whose electron configuration is given, we can do it by two methods.

Number 1. Sum all the exponents the result will give you the atomic number of the element.

2 + 2 + 6 + 2 + 6 = 18

The element with an atomic number of 18 is Argon.

Number 2. Look at the last terms of the electronic configuration

3s² 3p⁶

Number three indicates that this element is in the third period in the periodic table.

Sum the exponents 2 + 6 = 8

Number 8 indicates that this element is the number 8 of that period without considering the transition elements.

The element with these characteristics is Argon.

4 0

3 years ago

Read 2 more answers

Acids increase the concentration of __________ in a solution

Rufina [12.5K]

A. hydroxide is the answer

3 0

4 years ago

Read 2 more answers

The tosylate of (2R,3S)-3-phenylbutan-2-ol undergoes an E2 elimination on treatment with sodium ethoxide. Draw the structure of

andrezito [222]

Answer:

(R)-but-3-en-2-ylbenzene

Explanation:

In this reaction, we have a very strong base (sodium ethoxide). This base, will remove a hydrogen producing a double bond. We know that the reaction occurs through an E2 mechanism, therefore, the hydrogen that is removed must have an angle of 180º with respect to the leaving group (the "OH"). This is known as the anti-periplanar configuration.

The hydrogen that has this configuration is the one that placed with the dashed bond (red hydrogen). In such a way, that the base will remove this hydrogen, the "OH" will leave the molecule and a double bond will be formed between the methyl and the carbon that was previously attached to the "OH", producing the molecule (R) -but-3- en-2-ylbenzene.

See figure 1

I hope it helps!

6 0

4 years ago