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IrinaVladis [17]
3 years ago
12

Why is the spectroscope scale illuminated?

Chemistry
1 answer:
babunello [35]3 years ago
6 0

Answer:

The spectroscope scale is illuminated so that one can know exactly where the wavelengths of the lines are falling along.

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The change in internal energy for the combustion of 1.0 mol of octane at a pressure of 1.0 atm is -5084.1 kj . f the change in e
TEA [102]

<u>Given:</u>

Change in internal energy = ΔU = -5084.1 kJ

Change in enthalpy = ΔH = -5074.3 kJ

<u>To determine:</u>

The work done, W

<u>Explanation:</u>

Based on the first law of thermodynamics,

ΔH = ΔU + PΔV

the work done by a gas is given as:

W = -PΔV

Therefore:

ΔH = ΔU - W

W = ΔU-ΔH = -5084.1 -(-5074.3) = -9.8 kJ

Ans: Work done is -9.8 kJ


6 0
3 years ago
A solid keeps its shape due to which of the following factors? (3 points)
algol [13]

Answer: Attractive forces between particels

Explanation:

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Hawaii, which sits over a hot spot located near the center of the Pacific
Gnoma [55]

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Shield Volcano . I've been their before

Explanation:

4 0
3 years ago
Which of the following is the empirical formula for C4H8?
TEA [102]
It would be CH2! you’re just simplifying C4H8, 4 can go into C4 1 time (so we just say C) and 4 can go into H8 2 times (H2)
7 0
3 years ago
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Use the molar heat capacity for aluminum from table 1 to calculate the amount of energy needed to raise the temperature of 260.5
Nimfa-mama [501]
Unfortunately, you failed to include the table 1 from which the molar heat capacity of aluminum could have been obtained. However, as a general rule, the heat needed to raise the temperature of a certain substance by certain degrees is calculated through the equation,
                            H = mcpdT
where H is heat, m is mass, cp is specific heat capacity, and dT is change in temperature. From a reliable source, cp for aluminum is equal to 0.215 cal/g°C. Substituting this to the equation,
                               H = (260.5 g)(0.215 cal/g°C)(125°C - 0)
                                        H = 7000.94 cal
6 0
3 years ago
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