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natta225 [31]
3 years ago
7

Why are non-metals dull in appearance as solids?

Chemistry
1 answer:
Inessa [10]3 years ago
6 0
Metalloids are metallic-looking brittle solids<span> that are either semiconductors or exist in semiconducting forms, and have amphoteric or weakly acidic oxides. Typical </span>nonmetals<span> have a </span>dull<span>, coloured or colourless </span>appearance<span>; are </span>brittle<span> when </span>solid<span>; are poor conductors of heat and electricity; and have acidic oxides.</span>
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Calculate the molarity of a solution that contains 200 g of copper (II) chloride( CuCl2) in 150 mL of solution.
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An aqueous solution of ammonium sulfate is allowed to react with an aqueous solution of calcium nitrate. The net ionic equation
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The complete question is:

An aqueous solution of ammonium sulfate is allowed to react with an aqueous solution of calcium nitrate.

The net ionic equation contains which of the following species (when balanced in standard form)?

a. 2NO3-(aq)

b. Ca2+(aq)

Answer:

b. Ca2+(aq)

Ca2+ (aq) + SO4^2-(aq) --------------> CaSO4(s)

Explanation:

The overall ionic equation is:

Ca2+(aq) + 2NO3-(aq) + 2NH4+(aq) + SO4^2-(aq) ---------------> CaSO4(s) + 2NH4NO3(aq)

The NO3- and NH4+ are spectator ions as they do not participate in the formation of the precipitate CaSO4.

The net ionic equation is:

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4 0
3 years ago
If an endothermic process absorbs 256j how many kilocalories are absorbed
Finger [1]
There are several units for expressing energy, Most common are joules and kilocalories.

The conversion factor of joule to kilocalories is 
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Thus, 256 J = 0.0611 kilocalories
8 0
2 years ago
Read 2 more answers
the Temperature of a sample of an ideal gas in a sealed 5.0 l container is raised from 27 oC to 77oC. If the initial pressure of
matrenka [14]
Answer:
              The pressure increases to 3.5 atm.

Solution:
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For initial and final states of a gas the equation is,

                                           P₁ / T₁  =  P₂ / T₂
Solving for P₂,
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Data Given;
                   P₁  =  3 atm

                   T₁  =  27 °C + 273  =  300 K
 
                   T₂  =  77 °C + 273  =  350 K

Putting values in eq. 1,

                                           P₂  =  (3 atm × 350 K) ÷ 300 K

                                           P₂  =  3.5 atm
7 0
3 years ago
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