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Sergeeva-Olga [200]
3 years ago
13

In the reaction, Zn(s) + 2 HCl(aq) --> ZnCl2 (aq)+ H2(g), 25 grams of Zn are reacted with 17.5 g of HCl. How many grams of H2

will be produced?
Chemistry
1 answer:
Gennadij [26K]3 years ago
3 0

Answer:

0.480 g of H₂ are produced, in the reaction.

Explanation:

This is the reaction:

Zn(s)  +  2HCl → ZnCl₂ (aq) +  H₂ (g)

We havethe mass of both reactants, so we must work with them to find out the limiting reactant and then, determine the amount of H₂ produced.

Let's convert the mass to moles ( mass / molar mass)

25 g / 65.41 g/mol = 0.382 moles Zn

17.5 g / 36.45 g/mol = 0.480 moles HCl

Ratio is 1:2, so 1 mol of Zn react with the double of moles of HCl.

0.382 moles of Zn would need the double of moles to react, so (0.382 .2) = 0.764 moles of HCl. → We only have 0.480 moles, so the acid is the limiting.

Now let's determine the moles of H₂ formed.

Ratio is 2:1, so If i take account the moles I have, I will produce the half of moles of my product.

0.480 moles / 2 = 0.240 moles of H₂ are produced.

To find out the mass, we must multiply mol . molar mass

0.240 mol . 2g/mol = 0.480 g

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Answer:

The answer is explained below

Explanation:

Put the steps of the carbon cycle in order using Step 1 as your starting point

Step 1: Bacteria, through nitrogen fixation and nitrification, convert nitrogen into a usable form. The animal dies and decomposes, returning nitrogen back to the soil. Once nitrogen is in usable form, it is taken up by plants and assimilated into proteins.. An animal eats a plant and the nitrogen becomes part of the animal’s proteins.

The steps taking in the carbon circle using step 1 as the starting point is as follows:

Step 1:  Bacteria, through nitrogen fixation and nitrification, convert nitrogen into a usable form.

Bacteria convert nitrogen into nitrites and nitrates through the process of nitrification. Nitrites and nitrates are in the form that can be used by the plants

Step 2: Once nitrogen is in usable form, it is taken up by plants and assimilated into proteins.

The Nitrogen can only be used by the plants when in nitrites and nitrates form. When in this form, it is then assimilated into plant tissue as protein.

Step 3: An animal eats a plant and the nitrogen becomes part of the animal’s proteins.

An animal such as rabbit eats the plant and the protein in the plant becomes protein in the animal.

Step 4: The animal dies and decomposes, returning nitrogen back to the soil.

When the animal dies, the animal undergoes decomposition and the nitrogen in the animal is returned to the soil

5 0
3 years ago
Why is it beneficial for chemists to understand as many periodic trends as they can?
Alexandra [31]

Answer:

It can help identify elements quicker.

Explanation:

3 0
3 years ago
PLEASEEEEE HELP ME ON QUESTION 8 ASAP!!!!!!!!!!!!!!!!!!! GIVING 20 POINTS
spayn [35]

Answer:

I am pretty sure the correct answer is a reproductive system

3 0
2 years ago
Calculate the heat change involved when 2.00 L of water is heated from 20.0/C to 99.7/C in
Pani-rosa [81]

Answer:

666,480 Joules or 669.48 kJ

Explanation:

We are given;

  • Volume of water as 2.0L or 2000 ml

but, density of water is 1 g/ml

  • Therefore, mass of water is 2000 g
  • Initial temperature as 20 °C
  • Final temperature as 99.7° C

Required to determine the heat change

We know that ;

Heat change = Mass × Temperature change × specific heat

In this case;

Specific heat of water is 4.2 J/g°C

Temperature change is 79.7 °C

Therefore;

Heat change = 2000 g × 79.7 °C × 4.2 J/g°C

                      = 669,480 Joules 0r 669.48 kJ

Thus, the heat change involved is 666,480 Joules or 669.48 kJ

5 0
3 years ago
Enter a chemical equation for HI(aq) showing how it is an acid or a base according to the Arrhenius definition. Consider that st
jek_recluse [69]

Answer:

HI (aq) → H⁺ (aq) +  I⁻ (aq)

HI (aq) +  H₂O(l)  → H₃O⁺ (aq) +  I⁻ (aq)

Explanation:

The Arrhenius acid concept indicates that a substance behaves like acid if it produces hydrogen ions H⁺ or hydronium ions H₃O⁺ in water. A substance will be classified as a base if it produces OH⁻  hydroxide ions in water. This way of defining acids and bases works well for aqueous solutions.

When we mix HI (aq) and water, we are increasing [H₃O⁺]

HI (aq) → H⁺ (aq) +  I⁻ (aq)

HI (aq) +  H₂O(l)  → H₃O⁺ (aq) +  I⁻ (aq)

7 0
3 years ago
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