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2 years ago

How do you solve an equation with no symbol

Mathematics

1 answer:

Shtirlitz [24]2 years ago

7 0

Answer:

if it is it parenthesis it means to multiply. Every equation has to have an symbol all symbols are different but the same. If that equation have an letter you multiply that number times the letter.

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A cashier has a total of 30 bills consisting of ones, fives and twenties. the number of twenties is 5 less than the number of on

Varvara68 [4.7K]

Let us say that:

a = ones

b = fives

c = twenties

So that the total money is:

1 * a + 5 * b + 20 * c = 229

=> a + 5b + 20c = 229 --> eqtn 1

We are also given that:

c = a – 5 --> eqtn 2

a + b + c = 30 --> eqtn 3

Rewriting eqtn 3 in terms of b:

b = 30 – a – c

Plugging in eqtn 2 into this:

b = 30 – a – (a – 5)

b = 35 – 2a --> eqtn 4

Plugging in eqtn 2 and 4 into eqtn 1:

a + 5(35 – 2a) + 20(a – 5) = 229

a + 175 – 10a + 20a – 100 = 229

11a = 154

a = 14

So,

b = 35 – 2a = 7

c = a – 5 = 9

Therefore there are 14 ones, 7 fives, and 9 twenties.

7 0

3 years ago

Tasha believes that she can rewrite the difference of 120 minus 36 as a product of the GCF of the two numbers and the difference

xz_007 [3.2K]

Answer:

GCF = 12

For the values 36, 120:

Solution by Factorization:

The factors of 36 are: 1, 2, 3, 4, 6, 9, 12, 18, 36

The factors of 120 are: 1, 2, 3, 4, 5, 6, 8, 10, 12, 15, 20, 24, 30, 40, 60, 120

Then the greatest common factor is 12.

Pair Share:

The GCF of 120 and 36 is ======> 12

so, 120 – 36 can be written as:

12 × 10 – 12 × 3, which is 12 × (10 – 3) or 12 × 7.

Answer: ========> Therefore, Tasha is correct

Hope that helps!!!! : )

4 0

3 years ago

Please solve this problem<br> (9x+4)-(5x+3)

balandron [24]

I hope I can help!

(9x+4)-(5x+3)
4x + 7

7 0

2 years ago

Help solve 11 and 13 thanks mostly 11 xx

Gala2k [10]

Answer:

i also dont know

Step-by-step explanation:

8 0

2 years ago

Does the set {t, t Int} form a fundamental set of solutions for t^2y" -- ty' +y = 0?

Ivanshal [37]

Answer:

yes

Step-by-step explanation:

We are given that a Cauchy Euler's equation

$t^2y''-ty'+y=0$ where t is not equal to zero

We are given that two solutions of given Cauchy Euler's equation are t,t ln t

We have to find the solutions are independent or dependent.

To find the solutions are independent or dependent we use wronskain

$w(x)=\begin{vmatrix}y_1&y_2\\y'_1&y'_2\end{vmatrix}$

If wrosnkian is not equal to zero then solutions are dependent and if wronskian is zero then the set of solution is independent.

Let $y_1=t,y_2=t ln t$

$y'_1=1,y'_2=lnt+1$

$w(x)=\begin{vmatrix}t&t lnt\\1&lnt+1\end{vmatrix}$

$w(x)=t(lnt+1)-tlnt=tlnt+t-tlnt=t$ where t is not equal to zero.

Hence,the wronskian is not equal to zero .Therefore, the set of solutions is independent.

Hence, the set {t , tln t} form a fundamental set of solutions for given equation.

6 0

3 years ago