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bezimeni [28]
3 years ago
6

What is the mass in grams of 1.22 x 10 to the 24th power atoms of gallium?

Chemistry
2 answers:
UNO [17]3 years ago
6 0

Answer:

4355

Explanation:

bexause of 25 power

kap26 [50]3 years ago
3 0
Maybe it is I think 4355
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PLEASEEE HELPPP I SUCK AT CHEM :(
Luda [366]

Answer:

a) H2SO4 + 2KOH -> 2H2O + K2SO4

b) 9.809 ml

Explanation:

Number of Moles = Mass/ Molar Mass

Therefore: Mass = Number of moles * Molar Mass

--------------------------------------------

Molar mass of H2SO4:

H2= 2.02

S= 32.07

O4= 64

--------------------------------------------

H2SO4 has the molar mass of 98.09

--------------------------------------------

the Moles of H2SO4 is given to be 0.100M

Therefore:

Mass= 98.09*0.1

          = 9.809g

---------------------------------------------------

Assuming that 1 g= 1 ml, the volume of sulfuric acid is 9.809 ml.

7 0
3 years ago
I need help doing this please. It’s an image
Ne4ueva [31]

Answer:

k+

Ba2+

Al3+

K+

S2-

you may think that if it has a + it would be bigger, but it is actually the opposite.

5 0
3 years ago
An activated complex has
nignag [31]
The answer is D higher potential energy and is unstable
8 0
2 years ago
Perform the following operation and express the answer in scientific notation. 7.0x10^3x1.1x10^7
dimulka [17.4K]

Answer:

The answer is: 7.7\times10^{10}

Explanation:

Scientific notation is of the kind: a.bc\times10^{x}

The given calculation:

7.0\times10^{3}\times1.1\times10^{7}=(7\times1.1)\times10^{(3+7)}

=7.7\times10^{10}

Therefore, the answer in scientific notation is: 7.7\times10^{10}

4 0
3 years ago
When hydrogen sulfide reacts with oxygen, water and sulfur dioxide are produced. The balanced equation for this reaction is:
VMariaS [17]

Answer:

2H2S + 3O2 → 2SO2 + 2H2O

Explanation:

Step 1: Data given

Hydrogen sulfide = H2S

Oxygen = O2

sulfur dioxide = SO2

water = H2O

Step 2: The unbalanced equation

H2S + O2 → SO2 + H2O

Step 3: Balancing the equation

H2S + O2 → SO2 + H2O

On the left side we have 2x O (in O2) and on the right side we have 3x O (2x in SO2 and 1x in H2O). To balance the amount of O, we have to multiply O2 (on the left side) by 3 and SO2 and H2O on the right side by 3.

H2S + 3O2 → 2SO2 + 2H2O

On the right side we have 4x H and on the left side we have 2x H. To balance the amount of H, we have to multiply H2S by 2.

Now the equation is balanced.

2H2S + 3O2 → 2SO2 + 2H2O

7 0
3 years ago
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