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Elanso [62]
3 years ago
7

How many 250 mg tablets of metronidazole are needed to make 150 mL of suspension containing

Chemistry
1 answer:
Neko [114]3 years ago
7 0

Answer:

How many 250 mg tablets of metronidazole are needed to make 150 mL of suspension containing

100 mg/mL?

a. 25

b. 30

c.50

d. 60

Explanation:

<em>if </em><em> </em><em>mali </em><em>po </em><em>I'm</em><em> </em><em>so </em><em>sorry</em>

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What is the mass of 0.28 mole of iron?
vredina [299]

Answer:

Your answer should be 15.68 grams.

Explanation:

Seeing as 1 mole has a mass of 56 g, 56*0.28 would get you 15.68 g.

6 0
3 years ago
How many L are in 1,500cm^3<br><img src="https://tex.z-dn.net/?f=1500%7Bcm%7D%5E%7B3%7D%20%3D%20%5C%3A%20...%20%20%5C%3A%20liter
irga5000 [103]
1.5 liters are in 1,500cm^3.
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3 years ago
When there is a chemical reaction between hydrochloric acid and potassium hydroxide. Which substances are the reactants? Which s
Tasya [4]

Answer:

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Explanation:

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3 0
2 years ago
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An acetylide anion is more stable than either a vinylic or alkyl anion due to Group of answer choices the greater stability of a
sashaice [31]

Answer:

the stabilization of the negative charge in orbitals with higher s character

Explanation:

Acetylide anion is a carbon anion compound or popularly called carbanion. Now Acetylide anion is sp hybridized. However acetylide anion tends to be more acidic as we move from sp³ to sp, hence acidicity increases, which makes sp to have the highest acidity and become the most  stable.

So, we can conclude that the acetylide anion is more acidic due to the stabilization of the negative charge in orbitals with higher s character and  as the s character increases, acidic nature of acetylide anion also increases.

5 0
3 years ago
Pyridine (c5h5n) is a particularly foul-smelling substance used in manufacturing pesticides and plastic resins. calculate the ph
zubka84 [21]

Answer is: ph value of pyridine solution is 9.1.

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c(pyridine - C</span>₅H₅N) = 0.115M.<span>
Kb(C</span>₅H₅N) = 1.4·10⁻⁹.
[C₅H₅NH⁺] = [OH⁻] = x; equilibrium concentration.<span>
[</span>C₅H₅N] = 0.115 M - x.

Kb = [C₅H₅NH⁺] · [OH⁻] / [C₅H₅N].

1.4·10⁻⁹ = x² / (0.115 M -x)

Solve quadratic equation: x = [OH⁻] = 0.0000127 M.<span>
pOH = -log(0.0000127 M) = 4.9</span>

<span>pH = 14 - 4.9 = 9.1.</span>

7 0
3 years ago
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