Answer:
The concentration of the dilute sample will be 0.361 g/ml
Explanation:
If a solution is diluted into 1:10 ratio then the amount of solute of that solution will be decreased by 10 times.
The initial concentration of the stock solution was 3.61g/ml but when the solution is diluted in 1:10 ratio the solute concentration is also decreased by 10 times.SO at present the solute concentration becomes 3.61/10=0.361 g/ml.
The mole fraction of pentane in the vapor is 0.291
Vapour pressure rises with temperature and is a measurement of a substance's propensity to transform into a gaseous or vapour state. The boiling point of a liquid is the temperature at which the pressure exerted by its surroundings equals the vapour pressure present at the liquid's surface.
The number of moles of a particular component in the solution divided by the overall number of moles in the sample solution is known as the mole fraction.
Using the formula for vapour pressure,
vapour pressure =
°
×
+
°
× 
vapour pressure = 151 × 

+ 425 × 
240 = 151 - 151
+ 425
240 - 151 = - 151
+ 425 
89 = 274 
= 
0.291 = 
Therefore, the mole fraction of pentane in the vapor is 0.291
Learn more about vapour pressure here;
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The balanced chemical reaction would be expressed as follows:
2Na + Cl2 = 2NaCl
We are given the amount of sodium metal to be used reaction. This would be the starting value for the calculations. We do as follows:
6.25 g ( 1 mol / 22.99 g ) ( 1 mol Cl2 / 2 mol Na ) ( 22.4 L / 1 mol ) = 3.045 L Cl2 needed
Hope this answers the question.