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VMariaS [17]
3 years ago
14

Do carbohydrates always contain phosphorus

Chemistry
1 answer:
viva [34]3 years ago
5 0
Yes of course true true
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What are some uses for graphite
erma4kov [3.2K]
Because it is a solid material, it is known as a dry lubricant. This is useful inapplications<span> where “wet” lubricants, such as oil, cannot be </span>used<span>. </span>Graphite<span> is the only non-metal element that is a good conductor of electricity. Natural </span>graphite<span> is </span>used <span>mostly in what are called refractory </span><span>applications</span>
4 0
3 years ago
Evaluate the exponential expression (−2)6.
Olegator [25]

A general exponential expression is something like:

A^n

This means that we need to multiply the number A by itself n times.

Using that we will get (-2)^6 = 64

With that definition, we can rewrite:

(-2)^6 = (-2)*(-2)*(-2)*(-2)*(-2)*(-2)

So we just need to solve the above expression.

Also, remember the rule of signs:

(-)*(-) = (+)

We will get:

(-2)*(-2)*(-2)*(-2)*(-2)*(-2) =  [(-2)*(-2)]*[(-2)*(-2)]*[(-2)*(-2)]

                                        =  4*4*4 = 16*4 = 64

Then we got:

(-2)^6 = 64

If you want to learn more, you can read:

brainly.com/question/17172630

6 0
2 years ago
A mixture of ethyl acetate vapour and air has a relative saturation of 50% at 303 K and a total pressure of 100 kPa. If the vapo
AURORKA [14]

Answer : The correct option is, (b) 0.087

Explanation :

The formula used for relative saturation is:

\text{Relative saturation}=\frac{P_A}{P_A^o}

where,

P_A = partial pressure of ethyl acetate

P_A^o = vapor pressure of ethyl acetate

Given:

Relative saturation = 50 % = 0.5

Vapor pressure of ethyl acetate = 16 kPa

Now put all the given values in the above formula, we get:

0.5=\frac{P_A}{16kPa}

P_A=8kPa

Now we have to calculate the molar saturation.

The formula used for molar saturation is:

\text{Molar saturation}=\frac{P_{vapor}}{P_{\text{vapor free}}}

and,

P(vapor free) = Total pressure - Vapor pressure

P(vapor) = P_A = 8 kPa

So,

P(vapor free) = 100 kPa - 8 kPa = 92 kPa

The molar saturation will be:

\text{Molar saturation}=\frac{P_{vapor}}{P_{\text{vapor free}}}

\text{Molar saturation}=\frac{8kPa}{92kPa}=0.087

Therefore, the molar saturation is 0.087

5 0
3 years ago
Which is the most effective action for people to take in order to reduce greenhouse gas emissions? O taking the bus more often O
n200080 [17]

Answer:

Taking the bus more often

8 0
3 years ago
Read 2 more answers
if you have a solution that contains 46.85 g of codeine, C18H21NO3, in 125.5 g of ethanol, C2H5OH, what is the mole fraction of
OverLord2011 [107]

Answer:

The mole fraction of codeine is 5.4%

Explanation:

Mole fraction = Mole of solute / Total moles (Mole solute + Mole solvent)

Solute (Codeine)

Molar mass 299.36 g/m

Mass / Molar mass = Mole →  46.85 g /299.36 g/m = 0.156 moles

Solvent (Ethanol)

Molar mass 46.07 g/m

125.5 g / 46.07 g/m = 2.724 moles

Mole fraction (Codeine) 0.156 / (0.156 + 2.724) → 0.054

3 0
2 years ago
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