A. Exothermic<br> B. Isothermic<br> C. Endothermic

Propane burns in oxygen to produce carbon dioxide and water what is the percent yeild

amid [387]

Answer:

The percentage yield is 78.2g

Explanation:

Given, mass of propane = 42.8 g , sufficient O2 percent yield = 61.0 % yield.

Reaction - C3H8(g)+5O2(g)------> 3CO2(g)+4H2O(g)

First we need to calculate the moles of propane

Moles of propane = $\frac{42.8}{44.096}$ g.mol-1

= 0.971 moles

So, moles of CO2 from the moles of propane

1 mole of C3H8(g) = 3 moles of CO2(g)

So, 0.971 moles of C3H8(g) = ?

= 2.913 moles of CO2

So theoretical yield = 2.913 moles $\times$ 44.0 g/mol

= 128.2 g

So, the actual mass of CO2 = percent yield $\times$ theoretical yield / 100 %

= 61.0 % $\times$ 128.2 g / 100 %

= 78.2 g

the mass of CO2 that can be produced if the reaction of 42.8 g of propane and sufficient oxygen has a 61.0 % yield is 78.2 g

4 0

3 years ago

NEED HELP ASAP!!!!!!

Alinara [238K]

Explanation:

(1)

True

The winds are significant in the distribution of heat across the globe. There are global air circulations around the world such as the Hadley and polar cells that take heat from the hotter regions to the cooler regions. This is driven by high and low-pressure systems on earth that are influenced by the sun. Cooler air masses move from the high-pressure system and displace the warm winds in the low-pressure systems. This helps in maintaining a heat balance on earth.

(2)

False

The geosphere not only includes all the rocks on the surface of the earth but also the whole of the lithosphere ( or crust), which also includes all the landforms on earth. All the rocks and minerals in the interior of the earth are also part of the geosphere, including the process – such as the convection currents of the mantle- that helps in the shaping of the earth's surface.

(3)

A.

In a storm, the heat from the hydrosphere which is transferred to the atmosphere via the heat of evaporation is what feeds the storm. Therefore these two spheres not only share distribution of heat energy but also water. When the storms dissipate the heat and its water from the clouds, the water flows back to the hydrosphere and the cycle continues.

(4)

True

The biosphere includes all the living and biotic components on earth. Therefore even the marine animals in the oceans are part of the biosphere. They are one aspect that signifies the interaction betwene the hydrosphere and the biosphere. These organisms draw oxygen, water and minerals from the hydrosphere which is important or life.

(5)

True

However, the atmosphere is not the only sphere that distributes heat across the globe. So does the hydrosphere. The ocean's currents are very significant with this regard just as are air currents, The warm surface currents from the equator distribute heat towards the poles while cooler deeper currents flow towards the equator from the poles – maintaining a heat balance on earth.

(6)

D.

When a volcano erupts, gases -like sulfur dioxide and carbon dioxide- and pyroclasts from deep in the earth rocks (geosphere) are spewed into the atmosphere. This is an example of how these two spheres of the earth interact.

Learn More:

For more on spheres of the earth check out;

brainly.com/question/10893114

brainly.com/question/825370

brainly.com/question/10893109

#LearnWithBrainly

8 0

3 years ago

Value of Δ H ∘ rxn for the equation NH 3 ( g ) + 2 O 2 ( g ) ⟶ HNO3 ( g ) + H 2 O ( g )

koban [17]

Answer: - 894.6 kJ/mol.

Explanation:

Hess law is states that the changes in enthalpies in a chemical reactions is independent of the pathway between the initial and final states.

∆H is the change in the sum of the internal energy of a system.

We are to find the Value of ΔH°(rxn) for the equation:

NH3 (g) + 2 O2 (g) ⟶ HNO3 (g) + H2O (g). ----------------------------------(**).

From the series of equations given;

==> 4NH3 (g) + 5O2 (g) -------->4 NO(g) + 6H2O (l). ∆H = -1166.0 kJ/mol.--------------------------------------(1).

===> 2NO(g) + O2 (g) ------> 2NO2 (g). ∆H = -116.2 kJ/mol.---------------(2).

===> 3NO2 (g) + H2O (l) ---------> 2HNO3 (aq) + NO (g). ∆H = -137.3 kJ/mol.-------------------------------------(3).

The first thing to do is to multiply equation (2) by 3. Also, multiply equation (3) by 2. This will give us equation (4) and (5) respectively.

6NO + 3 O2 ----------------> 6NO2. ∆H= 3 × (-116.2 kJ/mol) = -348.6 kJ/mol. ------------------------------------(4).

6NO2 + 2 H2O ----------------> 4HNO3 + 2 NO. ∆H= 2 × (-137.3kj/mol) = -274.6 kJ/mol ---------------------------(5).

Next, add equations (4) and (5) to give;

4NO +3O2 +2H2O -------------> 4HNO3. ∆H = -623.2 kJ/mol. -----(6).

Add this equation to the equation (1) from above, we have;

4NH3 + 8O2 --------------> 4HNO3 + 4H2O. ∆H= -1789.2 kJ/mol. --------(7).

Then, divide the equation (7) above by 2 to give us back the equation (**).

NH3 (g) + 2 O2 (g) ⟶ HNO3 (g) + H2O (g). ∆H= -894.6 kJ/mol.

Δ H^∘ (rxn)= - 894.6 kJ/mol.

5 0

3 years ago

What would happen if you added more than 5 mL of yeast solution to the H2O2?

Marat540 [252]

Answer: -

Hydrogen peroxide breaks down into water and oxygen.

2H₂O₂ → 2H₂O + O₂

The yeast present contains an enzyme called catalase which catalyses the reaction.

More the amount of the catalyst added, faster will be the decomposition of the hydrogen peroxide.

Thus if we added more than 5 mL of yeast solution to the 2H₂O₂, the breakdown would occur faster. Thus the bubbles and the accompanying fizz would be much more.

3 0

3 years ago

A process stream contains 450 mol/s benzene and 375 mol/s toluene. Calculate the mole fraction of benzene in the process stream.

Tema [17]

Answer:

0.5455

Explanation:

The moles of benzene in the process stream in 1 sec = 450 moles

The moles of toluene in the process stream in 1 sec = 375 moles

So, according to definition of mole fraction:

$Mole\ fraction\ of\ benzene=\frac {n_{benzene}}{n_{benzene}+n_{toluene}}$

Applying values as:

$Mole\ fraction\ of\ benzene=\frac {450}{450+375}$

<u>Mole fraction of benzene in the process stream = 0.5455</u>

7 0

4 years ago

A. Exothermic B. Isothermic C. Endothermic