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qaws [65]
3 years ago
5

Ions of the elements oxygen (O), sulfur (S), and selenium (Se) usually have charges of 2-. Ions of the elements fluorine (F), ch

lorine (Cl), and bromine (Br) usually have charges of 1-. This demonstrates that
Chemistry
2 answers:
Anton [14]3 years ago
5 0

Explanation:

As ions of the elements oxygen (O), sulfur (S), and selenium (Se) usually have charges of 2-. This means that all these elements are same group elements, that is, group 16.

And, it is known that elements of the same group tend to show similar chemical properties because they contain same number of valence electrons.

Similarly, ions of the elements fluorine (F), chlorine (Cl), and bromine (Br) usually have charges of 1-. Hence, all these elements are also of same group, that is, group 17.

Thus, we can conclude that the given situation demonstrates that elements in the same group share certain properties, and each group has unique properties.

balu736 [363]3 years ago
3 0
The presented elements contain anions (negative ions) and are non-metals. Non-metals are always going to have a negative charge
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Explanation:

This medication is used as a moisturizer to treat or prevent dry, rough, scaly, itchy skin and minor skin irritations (e.g., diaper rash, skin burns from radiation therapy). Emollients are substances that soften and moisturize the skin and decrease itching and flaking.

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How does electronegativity affects the type of intramolecular bond that is formed between atoms
Effectus [21]

Answer:

If the electronegativity difference between bonded atoms are too much high ionic bonds are formed if the electronegativity diference is 0.4 or less than 0.4 non polar covalnet bond formed the difference greater than 0.4 polar covalent bond formed.

Explanation:

Ionic bond:

It is the bond which is formed by the transfer of electron from one atom to the atom of another element.  

Both bonded atoms have very large electronegativity difference. The atom with large electronegativity value accept the electron from other with smaller value of electronegativity.

For example:

Sodium chloride is ionic compound. The electronegativity of chlorine is 3.16 and for sodium is 0.93. There is large difference is present. That's why electron from sodium is transfer to the chlorine. Sodium becomes positive and chlorine becomes negative ion.

Covalent bond:

It is formed by the sharing of electron pair between bonded atoms.  

The atom with larger electronegativity attract the electron pair more towards it self and becomes partial negative while the other atom becomes partial positive.

For example:

In water the electronegativity of oxygen is 3.44 and hydrogen is 2.2. That's why electron pair attracted more towards oxygen, thus oxygen becomes partial negative and hydrogen becomes partial positive.

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3 years ago
Sound _____.
AysviL [449]

Answer:

Sounds travels in transverse waves requires a medium to travel through

4 0
2 years ago
Read 2 more answers
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Vaselesa [24]

Answer:

Scientific Explanation of weather change and cause storms is described below in detail.

Explanation:

The weather is just the nature of the environment at any time, including items such as warmth, rainfall, air pressure, and cloud shelter. Daily variations in the weather are due to storms and winds. Seasonal variations are due to the Earth spinning nearby the sun. Warm beginnings often produce stormy weather as the heated air mass at the exterior rises above the cool air mass, creating clouds and storms.

4 0
3 years ago
The energy E of the electron in a hydrogen atom can be calculated from the Bohr formula: E = R_y/n^2 In this equation R_y stands
Katarina [22]

Answer:

The wavelength of the line in the emission line spectrum of hydrogen caused by the transition of the electron for the given energy levels is 5.23\times 10^{-5} m

Explanation:

Given :

The energy E of the electron in a hydrogen atom can be calculated from the Bohr formula:

E=\frac{R_y}{n^2}

R_y=2.18\times 10^{-18} J =  Rydberg energy

n =  principal quantum number of the orbital

Energy of 11th orbit = E_{11}

E_{11}=\frac{2.18\times 10^{-18} J}{11^2}=1.80\times 10^{-20} J

Energy of 10th orbit = E_{10}

E_{10}=\frac{2.18\times 10^{-18} J}{10^2}=2.18\times 10^{-20} J

Energy difference between both the levels will corresponds to the energy of the wavelength of the line which can be calculated by using Planck's equation.

E'=E_{10}-E_{11}=2.18\times 10^{-20} J-1.80\times 10^{-20} J

=E'=0.38\times 10^{-20} J

\lambda =\frac{hc}{E'} (Planck's' equation)

\lambda = \frac{6.626\times 10^{-34} Js\times 3\times 10^8 m/s}{0.38\times 10^{-20} J}

\lambda = 5.2310\times 10^{-5} m\approx 5.23\times 10^{-5} m

The wavelength of the line in the emission line spectrum of hydrogen caused by the transition of the electron for the given energy levels is 5.23\times 10^{-5} m

3 0
3 years ago
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