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3 years ago

6

-3x - 8 = 50 Anyone know how to solve this by elimination?

2 answers:

Sever21 [200]3 years ago

7 0

-14!!
explanation it’s bc I’m smart :)

nikklg [1K]3 years ago

4 0

-14 should be the answer

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Help my semester ends in 17 hours

Nata [24]

Find the lengths of the sides. Determine how long a right triangle side lengths are.

4 0

2 years ago

What is the explicit formula for this sequence -7, -4, -1, 2, 5

Nataliya [291]

Answer:

$\large\boxed{a_n=3n-10}$

Step-by-step explanation:

It's an arithmetic sequence.

$-4-(-7)=-4+7=3\\-1-(-4)=-1+4=3\\2-(-1)=2+1=3\\5-2=3$

The difference is constant.

The explicit formula of an arithmetic sequence:

$a_n=a_1+(n-1)d$

Substitute:

$a_1=-7,\ d=3$

$a_n=-7+(n-1)(3)$ <em>use distributive property</em>

$a_n=-7+3n-3\\\\a_n=3n+(-7-3)\\\\a_n=3n-10$

6 0

3 years ago

Finley’s pumpkin had a mass of 6.5 kilograms before he carved it. After carving it the pumpkin had a mass of 3.9 kilograms. What

katen-ka-za [31]

Hello.

The percent decrease in the mass of the pumpkin for this case will be given by:
(100 - (3.9 / 6.5) * 100) =
(100-60) =40%

After carving it, the pumpkin decreases a percent of 40% in the mass.

Have a nice day

4 0

3 years ago

Read 2 more answers

In an experiment, Mary will flip a coin 9 times. Will the relative frequency of her coin landing on heads be

vlabodo [156]

Answer:

so you add 9+9+9+9+9+9+9+9+9

6 0

2 years ago

2 tan 30°<br>II<br>1 + tan- 300

shusha [124]

Question:

$\frac{2tan30^{\circ}}{1 + tan^2(30^{\circ})}$

Answer:

$\frac{2tan30^{\circ}}{1 + tan^2(30^{\circ})}$ $= sin(60^{\circ})$

Step-by-step explanation:

Given

$\frac{2tan30^{\circ}}{1 + tan^2(30^{\circ})}$

Required

Simplify

In trigonometry:

$tan(30^{\circ}) = \frac{1}{\sqrt{3}}$

So, the expression becomes:

$\frac{2tan30^{\circ}}{1 + tan^2(30^{\circ})}$ $= \frac{2 * \frac{1}{\sqrt{3}}}{1 + (\frac{1}{\sqrt{3}})^2}$

Simplify the denominator

$\frac{2tan30^{\circ}}{1 + tan^2(30^{\circ})}$ $= \frac{2 * \frac{1}{\sqrt{3}}}{1 + \frac{1}{3}}$

$\frac{2tan30^{\circ}}{1 + tan^2(30^{\circ})}$ $= \frac{\frac{2}{\sqrt{3}}}{1 + \frac{1}{3}}$

$\frac{2tan30^{\circ}}{1 + tan^2(30^{\circ})}$ $= \frac{\frac{2}{\sqrt{3}}}{ \frac{3+1}{3}}$

$\frac{2tan30^{\circ}}{1 + tan^2(30^{\circ})}$ $= \frac{\frac{2}{\sqrt{3}}}{ \frac{4}{3}}$

Express the fraction as:

$\frac{2tan30^{\circ}}{1 + tan^2(30^{\circ})}$ $= \frac{2}{\sqrt 3} / \frac{4}{3}$

$\frac{2tan30^{\circ}}{1 + tan^2(30^{\circ})}$ $= \frac{2}{\sqrt 3} * \frac{3}{4}$

$\frac{2tan30^{\circ}}{1 + tan^2(30^{\circ})}$ $= \frac{1}{\sqrt 3} * \frac{3}{2}$

$\frac{2tan30^{\circ}}{1 + tan^2(30^{\circ})}$ $= \frac{3}{2\sqrt 3}$

Rationalize

$\frac{2tan30^{\circ}}{1 + tan^2(30^{\circ})}$ $= \frac{3}{2\sqrt 3} * \frac{\sqrt{3}}{\sqrt{3}}$

$\frac{2tan30^{\circ}}{1 + tan^2(30^{\circ})}$ $= \frac{3\sqrt{3}}{2* 3}$

$\frac{2tan30^{\circ}}{1 + tan^2(30^{\circ})}$ $= \frac{\sqrt{3}}{2}$

In trigonometry:

$sin(60^{\circ}) = \frac{\sqrt{3}}{2}$

Hence:

$\frac{2tan30^{\circ}}{1 + tan^2(30^{\circ})}$ $= sin(60^{\circ})$

3 0

3 years ago