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Oksi-84 [34.3K]
3 years ago
10

During launches, rockets often discard unneeded parts. A certain rocket starts from rest on the launch pad and accelerates upwar

d at a steady 3.10 m/s^2. When it is 240 m above the launch pad, it discards a used fuel canister by simply disconnecting it. Once it is disconnected, the only force acting on the canister is gravity (air resistance can be ignored). A)How high is the rocket when the canister hits the launch pad, assuming that the rocket does not change its acceleration?
B)What total distance did the canister travel between its release and its crash onto the launch pad?
Physics
1 answer:
Usimov [2.4K]3 years ago
6 0

Answer:

a) 919 mts

b) 392 mts

Explanation:

In order to solve this, we will use the formulas of acceletared motion problems:

(1)Y=Yo+Vo*t+\frac{1}{2}*a*t^2\\(2)Vf^2=Vo^2+2*a*y

We are looking to obtain the initial velocity of the canister right after it was relased, we will use formula (2):

Vf^2=(0)^2+2*(3.10)*(240)\\Vf=38.6 m/s

we need to calculate the time the canister takes to reach the ground, we will use formula (1):

0-240m=38.6*t+\frac{1}{2}(-9.8m/s^2)*t^2\\\\-4.9*t^2+38.6*t+240=0\\t=11.9seconds

in order to know the new height of the rocket we have to use the formula (1) again:

Y=240+38.6*(11.9)+\frac{1}{2}*(3.10)*(11.9)^2\\Y=919mts

We can calulate the total distance the canister traveled before reach the ground by (2):

(0)^2=(38.6)^2+2*(-9.8)*y\\Y=76m

So the canister will go up another 76m, so the total distance will be:

Yc=Yup+Ydown+240m\\Yc=76+76+240\\Yc=392 mts

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Answer:

Minimize the elevation or jump distance

Explanation:

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v_{f}=\sqrt{2*g*h}

where:

vf = final velocity [m/s]

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As we can see while there is higher height, at a higher speed will impact the ground.

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4 years ago
The bohr model of the atom addressed the problem of
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Rutherford's nuclear model stated that a cloud of negative electrons surround the nucleus however scientists realized that electrons in a cloud around the nucleus of an atom would be attracted to the nucleus, causing the atom to collapse. Thus Bohr's model proposed that electrons were contained in shells and they orbit the nucleus at fixed distances.
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3 years ago
A long wire carrying a 5.0 A current perpendicular to the (xy)-plane intersects the x-axis at x = -2.00 cm. A second parallel wi
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Answer:

a. 05cm from x axis

b. 8cm from x axis

Explanation:

If the net magnetic field is zero and the currents are in the same direction then the thanks point is between the currents i1 and i2 as show in the attachment below

a. Given that i1= 5A and i2=3A

Let assume the null point is xcm from current i1, then the null point will be (4-x)cm from current i2 since the total length is 4cm.

Now the magnetic field of the current i1 from the null point= to magnetic field of current i2 from the null point

B1=B2

μi1/2πx=μi2/2π(4-x)

i1/x=i2/(4-x)

5/x=3/(4-x)

20-5x=3x

8x=20

8x=2.5cm

since from the left of x axis is 2cm, then the null point is 2.5-2 which 0.5cm from the origin x axis.

The null point is 0.5cm from the origin x axis

b. If both current are flowing in opposite direction, the null point lies outside of the current.

Then with same analysis let assume the first current i1 is xcm from the null point and since the total length is 4cm the second current i2 will be (x-4)cm from the null point.

Also the magnetic field of the current i1 from the null point = to magnetic field of current i2 from the null point

B1=B2

μi1/2πx=μi2/2π(x-4)

i1/x=i2/(x-4)

5/x=3/(x-4)

5x-20=3x

2x=20

x=10cm.

This shows that the distance of the null point from current i1 is 10cm and the current i1 is 2cm from the x axis, then the null point is 10-2=8cm from the origin x axis.

The null point is 8cm from the x axis.

Check the attachment to see the diagram of the current and the null points

6 0
4 years ago
Show your work please ​
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Answer:

V = U + at

Explanation:

<u>Given the following data;</u>

Initial velocity = 0 (since the stone is starting from rest).

Final velocity = 32 m/s

Acceleration = g = 10 m/s²

Time = 3.2 seconds

To show that the speed of the stone when it hits the ground is 32 m/s, we would use the first equation of motion;

V = U + at

Where;

  • V is the final velocity.
  • U is the initial velocity.
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  • t is the time measured in seconds.

Substituting into the formula, we have;

32 = 0 + 10*3.2

32 = 0 + 32

32 = 32

<em>Proven: 32 m/s = 32 m/s</em>

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Answer:24888.8g

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