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Softa [21]
4 years ago
5

What is the most likely elevation of point B?a. 150 ftb. 200 ftc. 125 ftd. 225 ft​

Physics
2 answers:
zepelin [54]4 years ago
7 0

Answer:

D

Explanation:

erm i think its 225 ft?

Dahasolnce [82]4 years ago
3 0
C. 125 ft it’s simple
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3 years ago
In a certain region of space, a uniform electric field is in the x direction. A particle with negative charge is carried from x=
swat32

In a certain region of space, a uniform electric field is in the x direction. A particle with negative charge is carried from x=20.0 cm to x=60.0cm.

<h3>Where is the electric potential, when the particle moved?</h3>

The charge field system's electric potential energy rose. The particle experiences an electric force that is directed against the x-axis. It is pushed uphill by an outside force, which raises the potential energy.

When a charge to be moved against an applied electric field, electric potential energy is needed. A charge must be moved through a stronger electric field with more energy than it would require to carry it via a weaker electric field.

In a certain region of space, a uniform electric field is in the x direction. A particle with negative charge is carried from x=20.0 cm to x=60.0cm.

The electric potential energy of the charge field system:

  • (a) increase
  • (b) remain constant
  • (c) decrease
  • (d) change unpredictably

The correct option is a).

To learn more about electric potential, refer to:

brainly.com/question/21808222

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7 0
2 years ago
¿Qué trabajo hace una fuerza de 110 N cuando mueve su punto de aplicación 20 mt en su misma dirección? *
lys-0071 [83]

Answer:

W = 2.200 Joules

Explanation:

Datos (data):

  • Fuerza [force] (F) = 110 N
  • Metros [meters] (m) = 20 m
  • Trabajo [work] (W) = ?

Usar la fórmula (use formula):

  • \boxed{\bold{W = F*d}}

Reemplazar (replace):

  • \boxed{\bold{W = 110\ N*20\ m}}

Resolver la multiplicación, recuerda que 1 N * 1 m = 1 J (resolve the multiplication, remember that 1 N * 1 m = 1 J:

  • \boxed{\boxed{\bold{W =2.200\ J}}}

Greetings.

7 0
3 years ago
Draco pushes a 3.2kg box with 1.5N of force. What is the resultant acceleration?
zlopas [31]

Answer:

0,46857

Explanation:

F=m*a

->a=F/m

6 0
3 years ago
A world-class sprinter can reach a top speed (of about 11.8 m/s ) in the first 19.0 m of a race. what is the average acceleratio
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We use the kinematic equation of motion, to calculate the average acceleration

v^{2} =u^{2} +2a (h-h_{0} )

or          a=\frac{v^{2} -v_{0}^2}{2(h-h_{0}) }

Here, v_{0} is initial speed , v is final speed  h is covered distance h_{0} is initial position.

Given  v= 11.8 m/s ,v_{0} =0 ,h = 19.0 m and h_{0} =0.

Substituting these values in above equation we get,

a=\frac{(11.8)^2-0}{2(19.0-0)} \\\\\ a =3.66 m/s^2

Thus, the average acceleration of the sprinter is 3.66 m/s^2.

6 0
3 years ago
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