What is the most likely elevation of point B?a. 150 ftb. 200 ftc. 125 ftd. 225 ft
2 answers:
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Answer:
the distance travelled from the bullet to the target is 391m
Explanation:
Hello! To solve this exercise we must follow the following steps.
1. the bullet travels with constant speed which means that the distance traveled to the target is given by the following equation
X=(V1)(T1)
where
X=target distance
V1=bullet speed=460m/s
T1=
time it takes for the bullet to reach the target
2. The distance the sound travels is given by the following equation (it is the same as the distance from the person to the target)
X=(V2)(T2)
X=
target distance
V2= speed of sound=340m/s
T2= time it takes the sound of the Bullet to return.
3. The total time it takes for the person to hear the bullet(T=2s) is the sum of the time it takes for the bullet to reach the target, plus the time it takes for the sound to reach the person, with the above we infer the following equation
T=T1+T2
2=T1+T2
4. Finally we use the equations found in step 1 and 2 to find the distance traveled using algebra.
the distance travelled from the bullet to the target is 391m
Answer:
0.345m
Explanation:
Let x (m) be the length that the spring is compress. If we take the point where the spring is compressed as a reference point, then the distance from that point to point where the ball is held is x + 1.1 m.
And so the potential energy of the object at the held point is:
where m = 1.3 kg is the object mass, g = 10m/s2 is the gravitational acceleration and h = x + 1.1 m is the height of the object with respect to the reference point
According to the conservation law of energy, this potential energy is converted to spring elastic energy once it's compressed
where k = 315 is the spring constant and x is the compressed length
x = 0.345 m or x = -0.263 m
Since x can only be positive we will pick the 0.345m