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3 years ago

A 2.2 ohm resistor has 0.042 A of current in it. What is the potential difference across the resistor?

Physics

1 answer:

Mrrafil [7]3 years ago

7 0

V=IxR
v =0.042x2.2
potential difference =0.0924volts

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The Surface Pressure at Leh, Ladakh is 800 mb. Now, assuming that Leh is at an altitude of 3500 m and every 100 m increase in he

Basile [38]

We have that the sea level pressure for Leh area is 1150mb mathematically given as

Ps= 1150 mb

<h3> Sea level pressure</h3>

Question Parameters:

Ladakh is 800 mb.

<u>assuming </u>that Leh is at an altitude of 3500 m and every 100 m

increase in height with respect to sea level corresponds to 10 mb pressure,

Generally, for 3500m the pressure change will be 350 mb.

Therefore, here for the sea level <em>pressure</em> we need to add,

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2 years ago

Use Kepler’s third law and the orbital motion of Earth to determine the mass of the Sun. The average distance between Earth and

dexar [7]

Kepler’s
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We’re trying to find M, so:

M=4pi^2*r^3/(G*T^2)

M=4pi^2*(1.496
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M=1.48× 10^40(m^3)/((N*m^2/kg^2)*days^2))

Let’s work
with the units:

(m^3)/((N*m^2/kg^2)*days^2))=

=(m^3*kg^2)/(N*m^2*days^2)

=(m*kg^2)/(N*days^2)

=(m*kg^2)/((kg*m/s^2)*days^2)

=(kg)/(days^2/s^2)

=(kg*s^2)/(days^2)

So:

M=1.48× 10^40(kg*s^2)/(days^2)

Now we need to convert days to seconds in order to cancel
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1 day=24 hours=24*60minutes=24*60*60s=86400s

M=1.48× 10^40(kg*s^2)/((86400s)^2)

M=1.48× 10^40(kg*s^2)/(
86400^2*s^2)

M=1.48× 10^40kg/86400^2

M=1.98x10^30kg

The
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(it may vary
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3 years ago

Read 2 more answers

What causes diffferent air density?

ololo11 [35]

Answer:

The temperature and gravity both affects the density

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3 years ago

A constant unbalanced force is applied to an object for a period of time. Which graph best represents the acceleration of the ob

balu736 [363]

Answer:

Here is an image attached with similar questions.

The correct answer is D where acceleration is function of time.

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The force acting on the object is constant.

There is no change in the application of forces.

And we know that Force is the product of acceleration and masses.

Newtons second law: $F=m\times a$

Regarding mass we know that it can neither be created nor destroyed.

So in $F=m \times a$ we have two constant terms, constant divided by constant will give the same result as $a=\frac{Force}{mass}$

There is no change in acceleration $(a)$ with respect to time $(t)$ .

So the most appropriate graph where time (t) is changing on $x-axis$ but acceleration doesn't changes is D.

The graph will be similar to $y=any\ constant$ and will be horizontal to the $x-axis$ .

Option D depicts the same.

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3 years ago

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makvit [3.9K]

<span>How hard the surfaces push together and the types of surfaces involved.</span>

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3 years ago