All categories

3 years ago

1. Determine which object will SINK or FLOAT in water.

Chemistry

1 answer:

zubka84 [21]3 years ago

8 0

Answer: Block # 1 , Block # 4 and

Block # 5 will sink.

Block # 2 and 3 will float.

Explanation: The density of water is equal to 1 g/mL. Any density that is less than the density of water will float. Objects with higher density compared to water will eventually sink.

You might be interested in

Which of the following lists the characteristics that all matter has?

motikmotik

It has mass and takes up space is correct.

5 0

3 years ago

Read 2 more answers

What volume of nitrogen gas is equal too 3.42x10^22 molecules of this substance

Bas_tet [7]

if i am correct the volume of nitrogen gas has to equal to molecules density, making the substance 1.27 liters :)

8 0

2 years ago

What are chemical formulaes?<br> give your own response!!

lbvjy [14]

Answer:

is a way of presenting information about the chemical proportions of atoms

Explanation:

8 0

3 years ago

An empty water bottle is full of air at 15°C and standard pressure. The volume of the bottle is 0. 500 liter. How many moles of

drek231 [11]

The moles of gas in the bottle has been 0.021 mol.

The ideal gas has been given as the gas where there has been negligible amount of interatomic collisions. The ideal gas equation has been given as:

$PV=nRT$

<h3>Computation for the moles of gas</h3>

The gi<em>ve</em>n gas has standard pressure, $P=1\rm atm$

The volume of the gas has been, $V= 0. 500 \;\rm L$

The temperature of the gas has been, $T=15^\circ \text C\\
T=288\;\rm K$

Substituting the values for the moles of gas, <em>n:</em>

<em />

<em /> $\rm 1\;\times\; 0. 500 =\textit n\;\times\;0.08214\;atm.L/mol.K\;\times\;288\;K\\\\
\textit n=\dfrac{0. 500}{0.08214\;\times\;288} \;mol\\\\
\textit n=0.021\;mol$

The moles of gas in the bottle has been 0.021 mol.

Learn more about ideal gas, here:
brainly.com/question/8711877

5 0

3 years ago

Calculate the mass of oxygen in 30 g of CH NH COOH?

Naya [18.7K]

Molar mass of CH2NH2COOH - 75

Given mass of CH2NH2COOH - 30

Moles of CH2NH2COOH = Given mass/ Molar mass

moles of CH2NH2COOH = 30/75 = 0.4 mol

One mole of CH2NH2COOH contains 32 gram of oxygen

0.4 mole of CH2NH2COOH will contain = 0.4 × 32= 12.8 g of oxygen

Answer- the mass of oxygen in 30 g of CH2NH2COOH is 12.8 gram!

7 0

2 years ago