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Ivenika [448]
3 years ago
5

What is a speed of 55 mph equivalent to in units of m/s? (1 mile = 1609 m, 1 hour = 3600 s)

Chemistry
1 answer:
jok3333 [9.3K]3 years ago
3 0

Answer:

24.58 m/s

Explanation:

Given that,

Speed of an object = 55 mph

We need to find the equivalent unit in m/s

We know that,

1 mile = 1609 m

1 hour = 3600 s

So,

55\ mph=\dfrac{55\times 1609\ m}{3600\ s}\\\\=24.58\ m/s

So, the required speed is 24.58 m/s.

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Answer:

The volume of 1.0 AgNO₃ that would be required to precipitate 5.84 grams of NaCl is 99.93 ml

Explanation:

Here we have the reaction of AgNO₃ and NaCl as follows;

AgNO₃(aq) + NaCl(aq)→ AgCl(s) + NaNO₃(aq)

Therefore, one mole of silver nitrate, AgNO₃, reacts with one mole of sodium chloride, NaCl, to produce one mole of silver choride, AgCl, and one mole of sodium nitrate, NaNO₃,

Therefore, since 5.84 grams of NaCl which is 58.44 g/mol, contains

Number \, of \, moles, n  = \frac{Mass}{Molar \ mass} =  \frac{5.84}{58.44} = 0.09993 \ moles \ of \ NaCl

0.09993 moles of NaCl will react with 0.09993 moles of AgNO₃

Also, as 1.0 M solution of AgNO₃ contains 1 mole per 1 liter or 1000 mL, therefore, the volume of AgNO₃ that will contain 0.09993 moles is given as follows;

0.09993 × 1 Liter/mole= 0.09993 L = 99.93 mL

Therefore, the volume of 1.0 AgNO₃ that would be required to precipitate 5.84 grams of NaCl is 99.93 ml.

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